Answer:
The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range for shelter B is 4.
Step-by-step explanation:
1) The line will need to be vertical down the point of x, meaning draw a line down point x. Perpendicular lines look similar to t’s
2.) Same thing, just draw a line through point O and the line. They should look similar to t’s
Hope this helped!! I understand math can get really hard, soon it’ll all be over :)
So " the line of best fit " would be 5(h) to 200(m) .
Which would also be 5:200 .
So after you can divide, so 5/5 would be 1 and 200/5 would be 40.
So it would be 1 to 40 (1:40).
The equation would be 40x.
If I helped please mark as brainliest . Thanks .
Answer:
The solution is (0, 4)
Step-by-step explanation:
Please pay attention to the first two equations and drop the last two:
12x−5y=−20 y=x+4 x=x=x, equals y=y=y should ideally be:
12x−5y=−20
y=x+4
Let's find x. Substitute x + 4 for y in the first equation, obtaining:
12x - 5(x + 4) = -20
Carrying out the indicated multiplication, we get:
12x - 5x - 20 = -20, or 7x = 0
If x = 0 then y must be 0 + 4, or 4.
The solution is (0, 4)
