Height of the water increasing is at rate of 
<h3>How to solve?</h3>
With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:
There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:
Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:
In the problem, we are given 
So we need to substitute this in:
Hence, Height of the water increasing is at rate of
<h3>Formula used: </h3>
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.....Jeremy did not make a good inference. The ratio is not in proportion to 2/15. The correct inference would be about 26 students who did not read any books in July. The sample might be biased since it was limited to those at the pool....
it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.
Let h(t) represent the height of the ball at time t.
Given that the height is given by:
h(t) = -16t² + 80t + 40
1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:
40 = -16t² + 80t + 40
16t² - 80t = 0
t(t - 5) = 0
t = 0 or t = 5
Hence it takes 5 seconds to reach a height of 40 ft.
2) The maximum height is at h'(t) = 0,
h'(t) = -32t + 80
-32t + 80 = 0
32t = 80
t = 2.5
It takes 2.5 seconds to reach maximum height.
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W-13=15|+13
w=15+13
x=28
<em>Answer: w=28</em>
We know that
[volume of a cone]=pi*r²*h/3
h=70 cm
r=15 cm
[volume of a cone]=pi*15²*70/3----------> 16485 cm³
if <span>Cathy uses 500 cm</span>³ of honey----------------> 1 day
<span>16485 cm</span>³--------------------------------------> X
<span>X=16485/500-----------> 32.97 days
the answer is 33 days </span>
