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cricket20 [7]
3 years ago
15

Jared made 12 3/4 cups of snack mix for a party.His guests eat 2/3 of the mix.How manysnack mix did his guest eat?

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

Answer:

<h3>The number of snacks did Jared's guest eat is 12\frac{1}{12}</h3>

Step-by-step explanation:

Given that Jared made 12\frac{3}{4} cups of snack mix for a party.

Let x be the cups of snacks mix made by Jared.

Therefore  x=12\frac{3}{4}

His guests eat \frac{2}{3} of the mix.

Let y be the guest eated snacks mix

Therefore y=\frac{2}{3}

<h3>To find how many snack mix did his guest eat :</h3>

Let z be the number of snacks did Jared's guest eat

Therefore z=x-y

z=12\frac{3}{4}-\frac{2}{3}

=\frac{51}{4}-\frac{2}{3}

=\frac{51(3)-2(4)}{4\times 3}

=\frac{153-8}{12}

=\frac{145}{12}

=12\frac{1}{12}

Therefore z=12\frac{1}{12}

<h3>Therefore the number of snacks did Jared's guest eat is 12\frac{1}{12}</h3>
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1. Find the value of 8.3 x 24.2 x 0.03. Round your answer to the nearest hundredth.
MrMuchimi

The rounded value is option B) 6.03 which is rounded to the nearest hundredth.

<u>Step-by-step explanation:</u>

  • To find the value of 8.3 x 24.2 x 0.03, we need to multiply the given numbers to get a decimal value.
  • And then, after getting the value of 8.3 x 24.2 x 0.03 it should be rounded to the nearest hundredth.

<u>So, let's multiply the numbers first :</u>

8.3 × 24.2 × 0.03 = 6.0258

The value is 6.0258

<u>To round the value 6.0258 to the nearest hundredth :</u>

  • The first number next to the decimal point represents the tenth.
  • The second number next to the decimal point is the hundredth.
  • The third number next to the decimal point is thousandth.

Therefore, to round the value to the nearest hundredth, look for the thousandth number is either less than 5 or greater and or equal to 5.

If, thousandth place is greater or equal to 5, then the hundredth number should be increased by 1.

The hundredth is 6.02 and the number in the thousandth place is 5. So add 1 to the hundredth place.

The value is rounded to 6.03 to the nearest hundredth.

5 0
3 years ago
Please help me with this and thank you
katovenus [111]

Answer:

The answer is D

Step-by-step explanation:

(12 + 6) x ( 11 - 7) = 72

18 x 4 = 72

72 = 72

5 0
3 years ago
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Drawing it out would be best can you help me please
leva [86]

Answer:

z_1+z_2 = (-2,5)

Step-by-step explanation:

To Find: z_1+z_2

Solution :

Referring the given graph

We can find the coordinates of   z_1 and  z_2

Coordinates of   z_1= (-7,1)

Coordinates of  z_2= (5,4)

Thus Coordinates of  z_1+z_2 = (-7+5,1+4) = (-2,5)

Thus z_1+z_2 = (-2,5)

So, the point z_1+z_2 = (-2,5) is shown on the attached graph file

6 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

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Question 1 (1 point)
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Answer:

97.2

Step-by-step explanation:

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