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Galina-37 [17]
3 years ago
9

PLEASE HELP

Mathematics
1 answer:
tester [92]3 years ago
6 0

Answer:

Step-by-step explanation:

a.infinite set of point on the line  

point on a chart that has no restrictions, and it tends to be extended.  

b. an empty set is otherwise called null set, it has no components persent in it. spoken to by { }  

c. point on quadrant 1.  

In quadrant 1, the two directions x and y must be certain. Any separation which has its reference with the source is known as a point.  

it very well may be determined by the formular Δy/Δx of the facilitate.

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1) Answer: \frac{x^{2}}{100} +\frac{y^{2}}{4} = 1

<u>Explanation:</u>

The equation of an ellipse is: \frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1 ; where (h, k) is the center, "a" is the x-radius, and "b" is the y-radius.

               Center                        Radius

x-axis:   (10 + -10)/2 = 0            10 - 0 = 10

  •       h = 0                             a = 10

y-axis:   (2 + -2)/2  = 0               2 - 0 = 2

  •       k = 0                             b = 2

Now, input the values into the equation:

\frac{(x-0)^{2}}{10^{2}} +\frac{(y-0)^{2}}{2^{2}} = 1

\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1

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2) Answer: \frac{x^{2}}{1} +\frac{(y+2)^{2}}{4} = 1

<u>Explanation:</u>

Vertices are: (0, 1) and (0, -5) ------> x-values are the same, y = 1, -5

Covertices are: (-1, -2) and (1, -2) ----> y-values are the same, x = -1, 1


               Center                        Radius

x-axis:   (-1 + 1)/2 = 0                  1 - 0 = 1

  •       h = 0                             a = 1

y-axis:   (1 + -5)/2  = -2               1 - (-2) = 3

  •       k = -2                             b = 3

Now, input the values into the equation:

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\frac{(x-0)^{2}}{1^{2}} +\frac{(y-(-2))^{2}}{3^{2}} = 1

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