All categories

3 years ago

ASAP ANSWER PLEASE :)

Mathematics

1 answer:

Hunter-Best [27]3 years ago

4 0

It is 3.33%

Origninally, the decimal continues with repetitive 3s.

You might be interested in

If f(x) = -8x + 8 and g(x) = (x–9,

icang [17]

Answer:

Step-by-step explanation:

(f ° g)(18) is another way of writing f(g(18)) which is telling you to evaluate function g at an x value of 18, then take that answer and plug it in for x in the function. Like this:

g(18) = 18 - 9 so

g(18) = 9. Now take that 9 and plug it into the f function in place of x:

f(9) = -8(9) + 8 and

f(9) = -72 + 8 so

f(9) = -64

3 0

3 years ago

Factorise x squared + 12 x + 35

Ksenya-84 [330]

5 and 7 add to make 12 and multiply to make 35 so those are the numbers that will be used:
(x+5)(x+7)

Hope this helps :)

5 0

4 years ago

The line plot shows how long you read during each reading session last week. What is the total time you read during these sessio

Diano4ka-milaya [45]

Answer: 15 1/2

Step-by-step explanation: There are two 1/2 s so 1/2 + 1/2 is 2/2 or 1 whole. Next is 1. There are 4 ones. 1+1+1+1 = 4. There is one 1 1/2. There are two 2. 2+2 is 4. There are two 2 1/2 so 2 1/2 + 2 1/2 is 4 2/2 which is 5. Now you have to add all the answers together. 1 +4+ 1 1/2 +4+5 which is 15 and 1/2. 15 1/2 is the answer.

5 0

4 years ago

Read 2 more answers

Which is an equivalent equation solved for y ?

Alborosie

D
divide both sides of the function by πx to get y=a/(πx)

7 0

3 years ago

Read 2 more answers

#24, i am getting <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%26%5Cfrac%7B18%7D%7B7%7D%20

sveticcg [70]

It looks like you're talking about row-reducing an augmented matrix to solve the system of equations. Your answer is almost correct. The last row should read 0, 0, 1, 2/7.

The given system translates to

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 1 & -1 & 2 & 2 \\ 1 & 2 & -3 & 4 \end{array} \right]$

Eliminate x from the last two rows by combining -2 (row 2) and row 1, and -2 (row 3) and row 1; that is,

(2x - 3y + z) - 2 (x - y + 2z) = 2 - 2 (2)

2x - 3y + z - 2x + 2y - 4z = 2 - 4

-y - 3z = -2

and

(2x - 3y + z) - 2 (x + 2y - 3z) = 2 - 2 (4)

2x - 3y + z - 2x - 4y + 6z = 2 - 8

-7y + 7z = -6

In augmented matrix form, this step yields

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & -7 & 7 & -6 \end{array} \right]$

I'll omit these details in the remaining steps.

Eliminate y from the last row by combining -7 (row 2) and row 3 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 28 & 8 \end{array} \right]$

Multiply the last row by 1/28 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Eliminate z from the second row by combining 3 (row 3) and row 2 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & 0 & -8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Multiply the second row by -1 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Eliminate y and z from the first row by combining 3 (row 2), -1 (row 3), and row 1 :

$\left[ \begin{array}{ccc|c} 2 & 0 & 0 & 36/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Multiply the first row by 1/2 :

$\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 18/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

8 0

3 years ago