Hello!
As we can see, our a value, which would be the coefficient of 
, which determines our slope, is negative, meaning that this whole line is negative.
Furthermore, the correlation can be determined using the r value of the linear regression, which is around -0.9.
If the r value of the linear regression is close to 1 or -1, let's say around |r| > 0.8, then we can consider the regression a strong correlation, meaning that this is a strong negative correlation, which is answer choice A.
Answer:
33/16
Step-by-step explanation:
x = y⁴/8 + 1/(4y²), 1 ≤ y ≤ 2
dx/dy = y³/2 − 1/(2y³)
Arc length is:
s = ∫ ds
s = ∫ √(1 + (dx/dy)²) dy
s = ∫₁² √(1 + (y³/2 − 1/(2y³))²) dy
s = ∫₁² √(1 + y⁶/4 − ½ + 1/(4y⁶)) dy
s = ∫₁² √(½ + y⁶/4 + 1/(4y⁶)) dy
s = ∫₁² ½ √(2 + y⁶ + 1/y⁶) dy
s = ∫₁² ½ √(y³ + 1/y³)² dy
s = ∫₁² ½ (y³ + 1/y³) dy
s = ½ (y⁴/4 − 1/(2y²)) |₁²
s = ½ (16/4 − 1/8) − ½ (1/4 − 1/2)
s = 33/16
Answer:
h'(1)=0
Step-by-step explanation:
We use the definition of the derivative of a quotient:
If 
, then:
Since in our case we want the derivative of 
at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:
which, by replacing with the given numerical values:
becomes:
Answer:
3^3 and 36^1
Step-by-step explanation:
3x3x3x3 is multiplying that 4 times so it is to the power of 4
36 is just once so it is to the power of one
