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lord [1]
2 years ago
6

The shipping department must send out 50 cases of phones. Five stores will receive ten cases each. How many cases are left?

Mathematics
2 answers:
netineya [11]2 years ago
5 0
Since 5x10 cases each = 50 cases there are no cases left.
scZoUnD [109]2 years ago
3 0
There are none left. 5 x 10 = 50
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120+34=154
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The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales
andrezito [222]

Answer:

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=44 represent the sample mean

s=1.9 represent the sample standard deviation

n=40 sample size  

\mu_o =42 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 42, the system of hypothesis would be:  

Null hypothesis:\mu \leq 42  

Alternative hypothesis:\mu > 42  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

3 0
3 years ago
Pigeonhole suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior. is t
Lady bird [3.3K]

Suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior: FALSE

<h3>What is a sophomore?</h3>
  • A sophomore in the United States is a student in their second year at an educational institution, usually a secondary school or a college or university, but also other types of post-secondary educational institutions.
  • A sophomore in high school is equivalent to a tenth-grade or Class-10 student.
  • In sports, a sophomore is a professional athlete in their second season.

As in the description, it is given that a sophomore in high school is equivalent to a tenth-grade or Class-10 student.

So, the above-given statement becomes false as it says that every student is a sophomore but the class has juniors and seniors.

Therefore, the statement "suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior" is FALSE.

Know more about sophomore here:

brainly.com/question/23382435

#SPJ4

The complete question is given below:

Suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior. Is the following statement true or false:

"The course must have at least five sophomores, or at least 20 juniors, or at least 10 seniors."

6 0
1 year ago
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Answer:

yes

Step-by-step explanation:

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y = - \frac{3}{4} x + 5 → (2)

Substitute y = \frac{3}{4} x + 6 into (2)

\frac{3}{4} x + 6 = - \frac{3}{4} x + 5 ( add \frac{3}{4} to both sides )

\frac{3}{2} x + 6 = 5 ( subtract 6 from both sides )

\frac{3}{2} x = - 1 ( divide both sides by \frac{3}{2} )

x = \frac{-1}{\frac{3}{2} } = - \frac{2}{3} ← one solution

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I’m very confused what are you trying to do here ?
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