Given :
An expression (cos 6m)(cos 2m) .
To Find :
We need to express it in terms as sum or difference.
Solution :
We know,
cos( A + B ) = cosA cos B - sin A sin B
cos( A - B ) = cosA cos B + sin A sin B
Adding both the equations we get :
2cos A cos B = cos( A + B) + cos( A - B )
or
cos A cos B = cos( A + B) + cos( A - B )/2
Putting value of A = 6m and B = 2m in above equation, we get :
(cos 6m)(cos 2m) = cos( 6m + 2m ) + cos( 6m - 2m )/2
(cos 6m)(cos 2m) = cos(8m) + cos(4m)/2
Hence, this is the required solution.
Answer:
B) Write out the relation in an x-y table and check that each x-value corresponds to the only one x - value
To isolate r, first divide both sides by pi. That will leave you with r^2=A/pi. Then square root both sides to completely isolate r.
r=<span>√A/pi</span>
Answer:
1468 in³
Step-by-step explanation:
First get get the total volume of the rectangular prism:
length l = 10 in
width w = 15 in
height h = 10 in
diagonal d = 20.6155281 in
total surface area Stot = 800 in²
lateral surface area Slat = 500 in²
top surface area Stop = 150 in²
bottom surface area Sbot = 150 in²
volume V = 1500 in
Now get get the volume from the missing rectangular prism:
ength l = 4 in
width w = 4 in
height h = 2 in
diagonal d = 6 in
total surface area Stot = 64 in²
lateral surface area Slat = 32 in²
top surface area Stop = 16 in²
bottom surface area Sbot = 16 in³
volume V = 32 in³
So 1500in³- 32 in³ =1468 in³
Here you go I hope this helps.
