The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
Answer:
24
Step-by-step explanation:
HI THERE LET ME HELP U WITH YOUR QUESTION
**PERFECT SQUARES ARE POSITIVE INTEGERS**<span>
</span>THE NUMBERS CANNOT INCLUDE ITSELF AND ALWAYS SHOULD HAVE A ONE IN IT.
2.89 AND 0.004 ARE PERFECT NUMBERS. THEY INCLUDE 1 AND THEY DONT INCLUDE ITSELF
HOPE IT HELPS
The answer is A. To understand that, you need to put it in order by the x's and the y's to get x^2-6x + y^2-16y = -48. Now complete the square on both the x and the y terms to get (x^2-6x+9) +(y^2-16y+64) = -48+9+64. Rewriting that in vertex form on the left and doing the math on the right gives you
(x-3)^2 + (y-8)^2 = 25, which shows you a center of (3,8) and a radius of 5.
Answer:
The probability of the spinner landing on 2 is one fourth.
Step-by-step explanation:
The spinner is split into 4 equal parts labeled 1, 2, 3, 4
The probability of the spinner landing on 2 is given as:
(Possibility of it landing on 2) ÷ (Total possible outcome)
The total possible outcome is 4, because the spinner could land on 1, or 2, or 3, or 4.
It can only land on 2 once, so the possibility of it landing on 2 is 1.
Probability = 1/4