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Dmitriy789 [7]
3 years ago
15

(False Converses) Write down the converse of each conditional statement about the integers. Then give a reason why the converse

is false.
If x is odd and y is odd, then x + y is even.
Mathematics
1 answer:
Mumz [18]3 years ago
8 0

Answer:

Converse: “If x+y is even, then x is odd and y is odd”

FALSE

Step-by-step explanation:

The converse of

“If x is odd and y is odd, then x+y is even”

is

“If x+y is even, then x is odd and y is odd”

The converse is false.

Counter-example:

Take x = 2, y = 4

Then x+y = 6 which is even, but neither x nor y are odd.

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Tính : <br>a) (a+b+c)^2<br>b) (a-b-c)^2<br>c) (a+b-c)^2<br>d) (a-b+c)^2
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Answer:

a.) a² + b² + c ² + 2ab + 2ac + 2bc

b.) a² + b² + c² - 2ab - 2 ac + 2bc

c ) a² + b² + c² + 2ab - 2ac - 2bc

d.) a² + b² + c² - 2ab + 2ac - 2bc

Step-by-step explanation:

  • Use ( a + b + c )² = a² + b² + c² + 2 × ab + 2 × ac + 2 × bc to expand all these expression

a) ( a + b + c )²

= a² + b² + c² + 2 × ab + 2 × ac + 2 × bc

= a² + b² + c ² + 2ab + 2ac + 2bc

b.) ( a - b - c )

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= a² + b² + c² - 2ab - 2 ac + 2bc

c.) ( a + b - c )²

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= a² + b² + c² + 2ab - 2ac - 2bc

d.) (a - b + c ) ²

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= a² + b² + c² - 2ab + 2ac - 2bc

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2 years ago
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