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Dmitriy789 [7]
4 years ago
15

(False Converses) Write down the converse of each conditional statement about the integers. Then give a reason why the converse

is false.
If x is odd and y is odd, then x + y is even.
Mathematics
1 answer:
Mumz [18]4 years ago
8 0

Answer:

Converse: “If x+y is even, then x is odd and y is odd”

FALSE

Step-by-step explanation:

The converse of

“If x is odd and y is odd, then x+y is even”

is

“If x+y is even, then x is odd and y is odd”

The converse is false.

Counter-example:

Take x = 2, y = 4

Then x+y = 6 which is even, but neither x nor y are odd.

You might be interested in
Which of the following represents a possible combination of books that Derek can buy?
Papessa [141]
It is most likely C if I am looking at it in need more information but if it is not C it is B
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B4%7D%20%20-%206%20%7Bx%7D%5E%7B3%7D%20%20%2B%2022%20%7Bx%7D%5E%7B2%7D%20%20-%2
alexira [117]

Answer:

x = 2, 1 + 3i, 1 − 3i

Step-by-step explanation:

Find the Roots (Zeros)

x^4 − 6x^3 + 22x^2 − 48x + 40

Set x^4 − 6x^3 + 22x^2 − 48x + 40 equal to 0. x^4 − 6x^3 + 22x^2 − 48x + 40 = 0

Solve for x.

Factor the left side of the equation.

Factor x^4 − 6x^3 + 22x^2 − 48x + 40 using the rational roots test.

(x − 2) (x^3 − 4x^2 + 14x − 20) = 0

 Factor x^3 − 4x^2 + 14x − 20 using the rational roots test.

(x − 2) (x − 2) (x2 − 2x + 10) = 0

 Combine like factors.

(x − 2)2 (x^2 − 2x + 10) = 0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

(x − 2)^2 = 0

x^2 − 2x + 10 = 0

 Set (x − 2)^2 equal to 0 and solve for x.

Set (x − 2)^2 equal to 0.

 (x − 2)^2 = 0

Solve (x − 2)^2 = 0 for x.

x = 2

 Set x^2 − 2x + 10 equal to 0 and solve for x.

Set x^2 − 2x + 10 equal to 0. x^2 − 2x + 10 = 0

Solve x^2 − 2x + 10 = 0 for x.

Use the quadratic formula to find the solutions.

−b ± (√b^2 − 4 (ac) )/2a

Substitute the values a = 1, b = −2, and c = 10 into the quadratic formula and solve for x.

2 ± (√(−2)^2 − 4 ⋅ (1 ⋅ 10))/2 ⋅ 1

Simplify.

Simplify the numerator.

  x =    2 ± 6i/ 2.1

Multiply 2 by 1

 x =  2 ± 6i/2⋅1

 Simplify

  2 ± 6i/2  

   x = 1 ± 3i

The final answer is the combination of both solutions.

x = 1 + 3i, 1 − 3i

The final solution is all the values that make (x − 2)2 (x2 − 2x + 10) = 0 true.

x = 2, 1 + 3i, 1 − 3i

3 0
3 years ago
A steel safe with mass 2200 kg falls onto concrete. Just
Virty [35]

The kinetic energy of the safe increases the force exerted by the concrete

to several times the weight of the safe.

  • The magnitude of the force exerted on the safe by the concrete on the is approximately \underline{29.\overline 3 \, \mathrm{MN}}
  • The concrete exerts a <u>force</u> that is approximately <u>1,359.16 times the weight of the safe</u>.

Reasons:

First part

The mass of the steel safe, m = 2,200 kg

Velocity of the safe just before it hits the concrete, v = 40 m/s

The amount by which the safe was compressed, d = 0.06 m

The kinetic energy, K.E., of the safe just before it hits the round is therefore;

\displaystyle K.E. = \mathbf{\frac{1}{2} \cdot m \cdot v^2}

\displaystyle K.E._{safe} = \frac{1}{2} \times 2,200 \times 40^2 = 1,760,000 \ Joules

Work done by concrete, W = Force, F × Distance, d

  • \displaystyle Force, \, F = \mathbf{\frac{Work, \, W}{Distance, \, d}}

By the law of conservation of energy, we have;

The work done by the concrete, W = The kinetic energy, K.E. given by the safe

W = K.E. = 1,760,000 J

The effect of the work = The change in the height of the safe

Therefore;

The distance, <em>d</em>, over which the force of the concrete is exerted = The change in the height of the safe = 0.06 m

d = 0.06 m

Therefore;

\displaystyle The \ force \ of \ the \ concrete, \, F = \frac{1,760,000\, J}{0.06 \, m} = 29,333,333. \overline 3 \, N = 29.\overline 3 \ MN

  • The force of the concrete on the safe = \underline{29.\overline 3 \ MN}

Second part:

The gravitational force of the Earth on the safe, W = The weight of the safe

W = Mass, m × Acceleration due to gravity, g

W = 2,200 kg × 9.81 m/s² ≈ 21,582 N

The ratio of the force exerted by the concrete to the weight of the safe is found as follows;

\displaystyle Ratio \ of \ forces = \frac{29.\overline 3 \times 10^6 \, N}{21,582 \, N} = \frac{4,000,000}{2,943} \approx \mathbf{1359.16}

  • The <u>force</u> exerted by the concrete is approximately <u>1,359.16 times the weight of the safe</u>.

Learn more here:

brainly.com/question/21060171

5 0
3 years ago
What would be the result if a was increased by 25 percent
zloy xaker [14]

Answer: formula - (x/4)+x

Step-by-step explanation:

Since there are no numbers, here is just the formula and what it means :)

(x/4)+x

(btw x is whatever your number is)

so what you need to do first is to divide your number by 4 because 25% is 1/4 of 100%

and then add that number that you just got to your number.

Its a little confusing to say out in words, so here is an example using 24

24/4=6

24+6=30

and heres another example using 50

50/4=12.5

50+12.5=62.5

I hope this helped! <3

6 0
3 years ago
A rectangle has a perimeter of 30 feet and an area of 50 square feet. What are the dimensions of the rectangle.
KiRa [710]

I believe the shorter sides are 5 feet and the longer ones are 10. This is because when you add up the two shorter sides as 10, and the other two as 20, then add them up to 30. That's the perimeter. For the area, you would do 10•5 to get 50 for the area

3 0
3 years ago
Read 2 more answers
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