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3 years ago

Is it possible for a composite number to have more than one prime factorization? Yes. I'm I right @dirtydan667

1 answer:

3 0

<span>Is it possible for a composite number to have more than one prime factorization?The Answer is Yes. Prime factors are factors of a composite number that are indivisible except by the number 1 or the number itself. it is possible especially for very large numbers. 2&3. No, because as mentioned previously, the default prime factors of numbers are 1</span>

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Marcy has 150 to buy packages of hotdogs and hamburgers for her booth at the carnival. Grocery store she found packages of hotdo

bekas [8.4K]

Answer:

Part (A): The required equation will be: $6d+20b=150$

Part (B):The required equation will be: $d=\frac{150-20b}{6}$

Part (C):The required equation will be: $b=\frac{150-6d}{20}$

Step-by-step explanation:

Consider the provided information.

Let d represents number of packages of hot dogs and b represents the number of packages of hamburgers.

Part (a)

It is given that the cost of a package of hot dogs is $6 and cost of a package of hamburger is $20.

The required equation will be: $6d+20b=150$

Part (b) Solve the above equation for d.

Subtract 20b from both sides.

$6d=150-20b$

Divide 6 from both sides.

$d=\frac{150-20b}{6}$

The required equation will be: $d=\frac{150-20b}{6}$

Part (c) Solve the equation for b.

Subtract 6d from both sides.

$20b=150-6d$

Divide 20 from both sides, we get

$b=\frac{150-6d}{20}$

The required equation will be: $b=\frac{150-6d}{20}$

6 0

3 years ago

Mary has $15 and she wants to buy some earrings. She picks one pair that costs $7.99 and two pairs that cost $2.59 each. Which s

Alika [10]

B. Estimation is good sometimes, but not in these cases.
Trust me, it's happened to me b4.

3 0

3 years ago

Read 2 more answers

BIG POINTS!!!+BRAINLIEST ANSWER! BONUS!!!

IgorC [24]

Answer:

Originally

The number of coins in the first box was $67\ coins$

The number of coins in the second box was $83\ coins$

Finally

The number of coins in the first box is $50\ coins$

The number of coins in the second box is $100\ coins$

Step-by-step explanation:

Let

x-----> number of coins in the first box originally

y-----> number of coins in the second box originally

we know that

$x+y=150$

$x=150-y$ -----> equation A

$(y+17)=2(x-17)$ -----> equation B

substitute equation A in equation B

$y+17=2x-34$

$y+17=2(150-y)-34$

$y+17=300-2y-34$

$y+2y=300-34-17$

$3y=249$

$y=83\ coins$

Find the value of x

$x=150-83=67\ coins$

therefore

Originally

The number of coins in the first box was $67\ coins$

The number of coins in the second box was $83\ coins$

Finally

The number of coins in the first box is $(67-17)=50\ coins$

The number of coins in the second box is $(83+17)=100\ coins$

4 0

3 years ago

Help!! please!!!! Solve x/10 = -7

inessss [21]

Answer:

Step-by-step explanation:

x/10=-7

Multiply both sides by 10 to isolate x.

x=-70

4 0

3 years ago

Sylvia earns $7 per hour at her after school job. After working one week, she received a paycheck for $91.

ANTONII [103]

Let the number of hours worked be "h," then the total amount is 7h=91.

4 0

3 years ago