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nikdorinn [45]
3 years ago
10

Ke Shawn is placing a right triangle in the coordinate plane. He knows that the longer leg is twice the length of the shorter le

g. He places the longer leg on the x-axis.
What coordinates should he assign to the third vertex of the triangle?

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0
If the length of the short leg is "a" then the length of the long leg should be "2a" and since the point is on the x axis the point is (2a,0) because the y=0
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There are 30 children eating ice cream. 2/5 of the children have chocolate. 1/3 of them have vanilla. The rest have strawberry.
defon

Answer:

28/2

Step-by-step explanation:

8 0
2 years ago
Solve the equation <img src="https://tex.z-dn.net/?f=8x%5E2%3D-36" id="TexFormula1" title="8x^2=-36" alt="8x^2=-36" align="absmi
chubhunter [2.5K]

Answer: 4(2x²+9) or i\frac{3\sqrt{2} }{2}

Step-by-step explanation:

To solve the equation by factoring, we want to set the equation to zero. In order to have the equation equal to zero, we want to add both sides by 36.

8x²=-36            [add both sides by 36]

8x²+36=0

When it comes to factoring, we want to pull out numbers or variables that are common in each term.

8x²+36=0         [take out a 4 in each term]

4(2x²+9)=0

It may seem that 2x²+9 can be factored further, it actually can't. This tells us that the factored form of the equation is 4(2x²+9)=0.

To solve the equation, we want to find the value of x. We already know the graph does not cross the x-axis because the y-intercept or vertex is (0,9).

4(2x²+9)=0       [divide both sides by 4]

2x²+9=0            [subtract both sides by 9]

2x²=-9               [divide both sides by 2]

x²=-9/2              [square root both sides]

x=\sqrt{-\frac{9}{2} } or x=i\frac{3\sqrt{2} }{2}

6 0
3 years ago
Read 2 more answers
PLEASE ANSWER ITS DUE SO SOON
geniusboy [140]

the line is negative because it goes down as you move right

slope = rise/run = 4/2 = 2

y = 2x+b

use a point on the line - I picked (-4, 3)

3 = 2(-4)+b

3 = -8+b

11 = b

<h2>y = 2x +11</h2>
8 0
3 years ago
How do we find 4and1/4 hours after 11:20pm?
tigry1 [53]

there are 60 minutes in 1 hour, so 1/4 of an hour is 60(1/4), namely 15 minutes.


11:20pm + 4 hours, is 11+4:20, namely 15:20, of course the time system only uses up to 12, so that has to be 3:20, and then we add the 15 minutes.


11+4: 20 + 15.........3:35am.

5 0
3 years ago
Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!
forsale [732]

1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}

Step-by-step explanation:

The given equation is 4x^{2}-8x-1

Let a be the coefficient of x^{2}

Let b be the coefficient of x

Let c be the constant.

Then the roots α,β for the equation ax^{2}+bx+c are \dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}

So,α=\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}

β=\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}.

So the roots are 1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}

5 0
3 years ago
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