Answer:
6n + 12
Step-by-step explanation:
Given an integer n, the 3 consecutive even integers greater than 2n are 2n+2, 2n+4 and 2n+6
Taking their sum;
Sum = (2n+2)+(2n+4)+(2n+6)
Sum = 2n+2n+2n+2+4+6
Sum = 6n + 12
Hence the sum of the 3 consecutive even integers greater than 2n is 6n+12
The attached graph represents the scatter plot of the table of values
<h3>How to create the scatter plot?</h3>
The table of values is given as:
Variable A 1 4 2 3 5 1 3 7 6 6 2 9 7 5 8
Variable B 6 6 1 6 7 4 4 7 5 3 5 25 21 4 4
Rewrite the table as:
x 1 4 2 3 5 1 3 7 6 6 2 9 7 5 8
y 6 6 1 6 7 4 4 7 5 3 5 25 21 4 4
Next, we plot the values on a graph
See attachment for the scatter plot
Read more about scatter plot at:
brainly.com/question/13984412
#SPJ1
Answer:
15
Step-by-step explanation:
A simple way is to go through the multiples of (because it is the biggest) and see the first number is divisible by 3
You can also just multiply 3 and 5
The solution for both ways is 15
If my answer is incorrect, pls correct me!
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-Chetan K
Answer:
D
Step-by-step explanation:
B and C aren't correct
