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Alenkasestr [34]
3 years ago
7

Find the specified lengths and measures. Given: ΔABC≅ΔDEF Find: AB and m∠F

Mathematics
1 answer:
Leya [2.2K]3 years ago
6 0

Answer:

Step-by-step explanation:

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Write 0.125 as if it was 2 to a power
Westkost [7]

Answer:

2^{-3}

Step-by-step explanation:

0.125 as a fraction is 125/1000 or 1/8

  • 1 is the same as 2^{0} (anything to the power of 0 is 1)
  • 8 is the same as 2³ (2 × 2 × 2 = 8)
  • 2^{0} ÷ 2³ = 2^{-3} (You subtract the powers: 0 - 3 = -3)

Hope this helps!

4 0
3 years ago
What is the value of x? Enter your answer in the box. x =
creativ13 [48]

x=5

a^+b^=c^

a^+12^=13^

a^+144=169

a^=25

a=square root of 25

a=5

4 0
3 years ago
This year, a herd of bison had 10% increase in population. If there was 550 bison in the herd last year, how many are in the her
sattari [20]

Answer: 605

Step-by-step explanation:

Last year            This year

550 x 1.1      =     605

7 0
3 years ago
Read 2 more answers
F(x) = 5x – 20 find f(6), f(10), and f(20)
damaskus [11]

Answer:

f(6) = 10, f(10) = 30, f(20) = 80

Step-by-step explanation:

Plug in the values into the equation and compute. 5*6 - 20 = 10, 5*10 - 20 = 30, 5*20 - 20 = 80.

8 0
3 years ago
Factor the GCF: -6x^4y^5 - 15x^3y^2 + 9x^2y^3
natta225 [31]
<span>-6x^4y^5 - 15x^3y^2 + 9x^2y^3

</span>-6x^4y^5 =  -2, 3, x, x, x, x,  y, y, y, y, y
15x^3y^2 =  -5, 3 x, x, x, y, y
9x^2y^3 =    3, 3 x, x, y, y, y

Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2

Divide that out and we get 
\frac{-6x^4y^5 - 15x^3y^2 + 9x^2y^3}{-3x^2y^2} =
2x^2y^3 + 5x - 3y
-3x^2y^2(2x^2y^3 + 5x - 3y)

5 0
3 years ago
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