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alina1380 [7]
3 years ago
5

The ability to roll one's tongue (turn up the sides) is controlled by a dominant allele. If two heterozygous parents have a chil

d, what are the chances an offspring will be able to roll their tongues?
Biology
1 answer:
Vanyuwa [196]3 years ago
7 0

the noise that you make is whistling

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For constipation, which grain, fruit, legume and vegetable would you recommend (based on chart below)
tester [92]
Good sources of dietary fiber including fruits vegetables, legumes and whole grains are highly recommended when one has constipation. Therefore; For constipation; i would recommend legumes such as beans, peas, and Lentils; Vegetables including Brococoli, spinach, The whole grains such as oatmeal, chia seeds, or flaxseeds, fruits such as berries, pears, apples and dried fruits.
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Which is a consumer?<br> A. algae<br> B. human<br> C. cabbage<br> D. carnation
QveST [7]

Answer:

Human

Explanation:

Everything else produces and photosynthesizes, humans are the only thing in the list that consumes

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3 years ago
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The wild-type form of a gene encodes a protein of length 100 amino acids. A mutant allele has a UAA (instead of the wild-type, C
Orlov [11]

Answer:

48 amino acids

Explanation:

The wild type gene codes for a protein with 100 amino acids. One amino acid is encoded by one triplet code of the gene. This means that the wild type gene has a total 100 triplets or 300 nucleotides to code for a protein of 100 amino acid. Mutation in this protein has introduced the code "UAA" at the 49th codon. The code "UAA" is a stop codon. Therefore, the mRNA transcribed from the mutant allele would code for a protein having 48 amino acids as the protein synthesis will be stopped once the stop codon at the 49th position is read.

8 0
3 years ago
Which layer does temperature zone does most precipitation occur?
siniylev [52]

Answer:

troposphere

Explanation:

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5 0
3 years ago
Two selectively permeable sacs A and B were submerged in a 45% glucose solution that was contained in a beaker. Sac A contained
Vesnalui [34]

Answer:

Option a. Only from Sac A to the beaker is correct.

Explanation:

As beaker contains glucose which is a monosaccharide and Sac A also have glucose in it, So, therefore glucose from sac A will move into beaker through the process of OSMOSIS.

Sac A (15% glucose) is less concentrated as compared to beaker (45% glucose) therefore this phenomenon will occur. (See attached image for more detailed and graphical explanation)

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