Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=1+(n-1)(-5.7)

Answer 1

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases}\\\\ -------------------------------\\\\ a(n)=1+(n-1)(-5.7)\qquad \begin{array}{llll} term&value\\ ---&------\\ a(1)&1+(1-1)(-5.7)\\ &1+0\\ &1\\ a(4)&1+(4-1)(-5.7)\\ &1+(3)(-5.7)\\ &1+(-17.1)\\ &-16.1\\ a(10)&1+(10-1)(-5.7)\\ &1+(9)(-5.7)\\ &1+(-51.3)\\ &-50.3 \end{array}$