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VARVARA [1.3K]
2 years ago
8

Într-un cimitir există 7 chiparoși și 288 tufe de tuia. La fiecare mormânt există cel puțin o tufă de tuia. Numărul celor cu dou

ă tufe este de trei ori mai mare de cât al celor cu trei tufe și de cinci ori mai mic decât al celor cu o singură tufă. Câte morminte sunt
Mathematics
1 answer:
svlad2 [7]2 years ago
5 0

Answer:

A cumparat 5 prajituri cu vanilie si 7 cu ciocolata.

Step-by-step explanation:

You might be interested in
Two consecutive odd integers have a sum of 32. Find the integers.
bezimeni [28]
Let
x = first consecutive odd
x + 2 = second consecutive odd

Based on the problem, we equate
x + (x + 2) = 32
Solving for x,
2x + 2 = 32
2x = 32 - 2
2x = 30
x = 30/2
x = 15
and x + 2 = 15 + 2 = 17

Therefore, the integers are 15 and 17.
6 0
3 years ago
I will give you the brainliest if you answer asap please
IRINA_888 [86]

Answer:

168

Step-by-step explanation:

You just need to triple the answer to get 168.

8 0
3 years ago
If you travel 70000 M at a rate of 25 m/s and , how long does it take to complete the trip?
ivolga24 [154]

Answer:

Time=2800 seconds.

Time in minutes= 46.67 minutes

Time in hours= 0.778 hours

Step-by-step explanation:

Distance traveled= 70000 m

Rate or speed of travel= 25m/s

To calculate the time for the travel, we multiply the rate of travel by the distance covered or traveled.

Rate= distance/time

Time= distance/rate

Time= 70000/25

Time=2800 seconds.

Time in minutes= 2800/60

Time in minutes= 46.67 minutes

Time in hours = 2800/(60*60)

Time in hours= 2800/360

Time in hours= 0.778 hours

8 0
3 years ago
In each part, decide if the statement is true. If it is true, prove it. If it is not true, give an explicit counterexample and d
svet-max [94.6K]

Answer: Hello!

ok, remember that "if and only if" implies that you need to prove the statement in both ways, this is represented with the ⇔ usually.

a) For any sets A, B and C, A ∩ B ⊆ C if and only if either A ⊆ C or B ⊆ C.

In this type of problems, i  find very useful start looking for some counterexample.

In this case, suppose that A = {1,2,3,4,5} , B = {3,4,5,6,7} and C = {3,4,5,6}

then is easy to see that A ⊄ C and B ⊄C.

And A∩B = {3,4,5}

then A∩B ⊂ C

then the statement is false (because one of the ways is false, remember that this is an "if and only if" statement)

b) For any sets A, B and C, A ⊆ B ∩ C if and only if both A ⊆ B and A ⊆ C.

the first way is true; because if A ⊆ B ∩ C. then all the elements of A are in the intersection of B and C (which are common elements for B and C) and then all the elements of A are in the set B and in the set C, and this means that A ⊆ B and A ⊆ C.

But let's see the other way now, suppose that A ⊆ B and A ⊆ C, now we want to know if A ⊆ B ∩ C.

if A ⊆ B and A ⊆ C, means that all the elements of A are in B, and all the elements of A are in C, then all the elements of A are common elements between B and C, this means that B ∩ C is at least equal to A (at least, because we know that all the elements of A are common elements between B and C, but there could be more common elements that don belong to A)

then A ⊆ B ∩ C.

4 0
3 years ago
Find the value of the trig functions indicated .
lara31 [8.8K]

Answer:

The choice; B) 5/3

Step-by-step explanation:

{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\  {15}^{2}  +  {20}^{2}  =  {c}^{2}  \\ 225 + 400 =  {c}^{2}  \\  {c}^{2}  = 625 \\ c = 25

\sec(θ)  =  \frac{1}{ \cos(θ) }  \\  \\  \sec(θ)  =  \frac{1}{ \frac{adjacent}{hypotenuse} }  =   \frac{hypotenuse}{adjacent}  \\  \\  \sec(θ)  =  \frac{25}{15}  =  \frac{25 \div 5}{15\div 5}  =  \frac{5}{3}

4 0
1 year ago
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