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Damm [24]
3 years ago
7

Solve 7x-4 = 5x+15 for x

Mathematics
1 answer:
tatiyna3 years ago
6 0

\bf{Hey\ there!}

\bf{7x-4 = 5x+15}

\bf{\underline{Subtract}\ 5x\ from\ \ on \ both\ of\ your\ sides!\downarrow}

\bf{7x-4-5x=5x+15-5x}

\bf{2x-4=15}

\bf{\underline{Add}\ by\ 4\ on\ each\ of\ your\ sides!\downarrow}

\bf{2x-4+4=15+4}

\bf{Cancel:-4+4\ because\ it\ equals\ 0}

\bf{Keep:15+4\ because\ it\ helps\  us\ solve\ for\ your\ answer}

\bf{15+4=19}

\bf{2x=19}

\bf{\underline{Divide}\ by\ 2\ on\ your\ sides!\downarrow}

\bf\frac{2x}{2}=\frac{19}{2}}

\bf{Cancel:\frac{2x}{2}\ because\ that\ gives\ you\ 1}

\bf{Keep:\frac{19}{2}\ because\ it\ gives\ you\ the\ the\ value\ of\ x}

\boxed{\boxed{\bf{Answer:x=\frac{19}{2}}}}\checkmark

\bf{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}

\frak{LoveYourselfFirst:)}

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Three polynomials are factored below, but some coefficients and constants are missing. All of the missing values of a, b, c, and
mariarad [96]

9514 1404 393

Answer:

  1. (a, b, c, d) = (1, -4, 1, -2)
  2. (a, b, c, d) = (1, -4, 1, 2)
  3. (a, b, c, d) = (1, -4, 2, 6)

Step-by-step explanation:

Once you remove the common factor from the terms, you are looking for factors of the remaining constant term that have a sum equal to the coefficient of the linear term. These factors are the constants in the binomial factors.

__

1. 8 = (-4)(-2)   ⇒   x^2 -6x +8 = (x -4)(x -2)

  (a, b, c, d) = (1, -4, 1, -2)

__

2. -8 = (-4)(+2)   ⇒   3x^3 -6x^2 -24x = 3x(x -4)(x +2)

  (a, b, c, d) = (1, -4, 1, 2)

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3. -12 = (-4)(3)   ⇒   2x^2 -2x -24 = 2(x -4)(x +3) = (x -4)(2x +6)

   (a, b, c, d) = (1, -4, 2, 6)  or  (2, -8, 1, 3)

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