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Rudiy27
4 years ago
14

In triangle XYZ,XY=15,YZ=21, and XZ=27. What is the measure of angle Z to the nearest degree?

Mathematics
1 answer:
sweet-ann [11.9K]4 years ago
7 0
15+21+27
63 degrees would be the nearest
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Velocity of a Car The velocity of a car (in feet per second) t sec after starting from rest is given by the function f(t) = 11 t
pochemuha

Answer:

<h2>s(t) = 11t²/2 </h2>

Step-by-step explanation:

Velocity is defined as the rate of change in displacement of a body. It is expressed mathematically as v = change in displacement/time

v(t) = ds(t)/dt

ds(t) = v(t)dt

integrating both sides;

s(t) =  \int\limits v(t)dt

Given the velocity function f(t) = 11t, the car's position (displacement) is expressed as s(t) = \int\limits 11t\ dt

s(t) = 11t²/2 + C

at the initial point, s(0) = 0 i.e when t = 0, s(t) = 0. The resulting equation becomes;

0 = 11(0)²/2+ C

0 = 0+C

C = 0

To find the car's position, s(t), we will substitute C = 0 into the equayion above;

s(t) = 11t²/2 + 0

s(t) = 11t²/2

Hence s(t) = 11t²/2  is the required position of the car in terms of t.

6 0
3 years ago
A cat can run 30 miles per hour. At this rate, how many minutes would it take a cat to run 1.5 miles?
vlabodo [156]

Answer:

3 minutes

Step-by-step explanation:

30/60 which is how many minutes are in an hour, gives you .5 miles per minute and .5 x 3 = 1.5miles

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Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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3 years ago
Read 2 more answers
A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?​
zzz [600]

Answer:

\boxed{ \bold{ \huge{ \boxed{  \sf 240 \:  {inches}^{2} }}}}

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

Area of a rectangle = ?

Let width of a rectangle be ' w ' .

<u>Fi</u><u>rst</u><u>,</u><u> </u><u>finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u>

\boxed{ \sf{perimeter = 2(l + w)}}

plug the values

⇒\sf{64 = 2(20 + w)}

Distribute 2 through the parentheses

⇒\sf{64 = 40 + 2w}

Swap the sides of the equation

⇒\sf{40 + 2w = 64}

Move 2w to right hand side and change it's sign

⇒\sf{2w = 64 - 40}

Subtract 40 from 64

⇒\sf{2w = 24}

Divide both sides of the equation by 2

⇒\sf{ \frac{2w}{2}  =  \frac{24}{2} }

Calculate

⇒\sf{w = 12 \: inches}

Width of a rectangle ( w ) = 12 inches

<u>Now</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>having</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>2</u><u>0</u><u> </u><u>inches</u><u> </u><u>and </u><u>width </u><u>of</u><u> </u><u>1</u><u>2</u><u> </u><u>inches</u>

\boxed{ \sf{area \: of \: rectangle = length \:  \times  \: \: width}}

plug the values

⇒\sf{area \: of \: rectangle =20 \times  12 }

Multiply the numbers : 20 and 12

⇒\sf{area \: of \: rectangle = 240 \:  {inches}^{2} }

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

7 0
3 years ago
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