Answer:
The program to this question can be given as:
Program:
factorial=1 #declare a variable.
number=int(input("Enter a positive integer:")) #input a number.
while (number>0): #loop
factorial= factorial*number # holding value in factorial variable
number=number-1
print('=',factorial) #print value.
Output:
Enter a positive integer:6
= 720
Explanation:
The description of the above python program can be given as:
- In the above program firstly we define a variable that is "factorial". In this variable, we assign a value that is 1 and it is used to calculate the factorial value.
- We define a variable "number". The number variable is used to take input from the user.
- Then we define a loop in the loop we calculate the factorial and hold the value in the factorial value in the last we print the value.
Answer:
The correct answer to the following question will be Option B (Algorithm).
Explanation:
- An algorithm seems to be a countable series of very well-defined, machine guidance that is implementable, and are generally used to solve a group of issues and to perform a calculation.
- It is widely used for processing of the data, computation and other associated computational and numerical activities.
- A coding algorithm is a process of the computer that's a lot like just a formula that tells the machine precisely what actions you need to follow to fix a problem or achieve a goal.
The other three options will not be able to fix the problems that arise while achieving a goal, execution of a function or creating program code.
Therefore, Option B is the right answer.
Answer:
It can be "ON" or "OFF". So it can store the numbers 1 and 0, but it certainly doesn't have the capacity to store a letter of the alphabet.
Explanation:
Answer:
rita should either ask the original author for permission to use her blog, but the best answer woyuld be that she should site her sources.
Explanation:
I believe it is called closed mindset. Closed mindset is when you fail to see other ways to your error and don't accept help or think you can improve.
