Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:
Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.81 times.
Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.
Answer:
b. typically contain more circuits in the network than in star or ring networks
Explanation:
In mesh architecture, all computers are connected to each other. In mesh all nodes connect directly and non hierarchical to each other so as to efficiently route data.
Mesh combines the benefits of both ring and star networks. It usually provide relatively short routes through the network (compared to ring networks) and provide many possible routes through the network to prevent one circuit from becoming overloaded (as compared to star network). Mesh network uses decentralized routing with each network performing its own routing.
Mesh network typically contain more circuits in the network than in star or ring networks and are more expensive than ring networks
Answer:
C. 1/60
Explanation:
Shutter speed is most commonly measured in fractions of a second, like 1/20 seconds or 1/10 seconds. Some high-end cameras offer shutter speeds as fast as 1/80 seconds. But, shutter speeds can extend to much longer times, generally up to 30 seconds on most cameras.
But in this case C. 1/60 is the answer.
