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aleksandrvk [35]
3 years ago
14

What fraction is equivalent to 0.46464646···

Mathematics
2 answers:
pashok25 [27]3 years ago
7 0

The answer is C. Hope we helped. 46 ends in the 100th place so it's just 46/100.


ICE Princess25 [194]3 years ago
3 0

For this case, we must divide each of the given fractions, to find one that is equivalent to 0.46464646 ···

Dividing we have the following:

\frac {46} {99} = 0.464646465\\\frac {46} {999} = 0.046046046\\\frac {46} {100} = 0.46\\\frac {23} {50} = 0.46

Finally, the correct fraction is \frac {46} {99}

Answer:

Option A


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enot [183]
Consider, please, this solution/explanation:
1. suppose, that number of cars is 'x', numbers of buses is 'y'.
2. according to the condition 'a total of 32', it means that x+y=32. This is the 1st equation.
3. according to the condition in one car are 3x persons, in one bus are 27y persons, and totaly 3x+27y=408 people. This is the 2d equation.
4. if to solve the system of two equations:
\left \{ {{x+y=32} \atop {3x+27y=408}} \right. \ =\ \textgreater \  \  \left \{ {{x=19 (cars)} \atop {y=13(buses)}} \right.

Answer: 13 - b., 19 - c.
6 0
3 years ago
Gio ran 5 miles yesterday. This distance is 80% of the distance he planned to run.
aleksklad [387]

Answer:

Gio planned to 6 miles.

Step-by-step explanation:

this is because  5 - 80% = 1

which means he wanted to run 1 more mile

which also means that he planned to run 6 miles

3 0
2 years ago
Read 2 more answers
Pls help I need a good grade
zvonat [6]

Answer:

p=5

Step-by-step explanation:

28-13=3p

15=3p

p=5

6 0
2 years ago
Read 2 more answers
PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the
drek231 [11]

Answer:

1) The height of the ball from 0 to 5  seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2)  The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0
3 years ago
Can someone help me with this question please?.
Taya2010 [7]
Answer: I think its n-12
3 0
3 years ago
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