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2 years ago

Find the inverse of y=100-x^2

Mathematics

1 answer:

AnnyKZ [126]2 years ago

5 0

Answer:

The inverse is ±sqrt(100-x)

Step-by-step explanation:

To find the inverse, exchange x and y

x = 100 -y^2

Solve for y

Subtract 100 from each side

x - 100 = -y^2

Divide by -1

-x +100 = y^2

Take the square root of each side

±sqrt(100-x) = sqrt(y^2)

±sqrt(100-x) =y

The inverse is ±sqrt(100-x)

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Five whole numbers are written in order

jeka57 [31]

Answer:

x=7

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Step-by-step explanation:

-Given that the mean and median is the same.

-Let b=mean =median

#Given that the set is arranged in order and is even:

$median=\frac{n+1}{2}\\\\Median=3^{rd} \ term\\\\=x$

Hence:

$b=median=mean\\\\b=x\\\\\therefore mean=median=x$

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$\bar x=\frac{1}{n}\sum{x_i}\\\\\therefore 5x=4+6+x+y+10\\\\4x=20+y\\\\x=5+0.25y$

#Since the number are in order:

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2 years ago

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AVprozaik [17]

Answer:

Step-by-step explanation:

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3 years ago

6/11+1/2 what is the answer

tester [92]

Answer:

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Step-by-step explanation:

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2 years ago

1. Explain how you can use a strightedge and a compass to construct an angle that is both congruent and adjacent to a given angl

andrew11 [14]

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2 years ago

Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$