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Dvinal [7]
3 years ago
11

If (-2, y) lies on the graph of y = 4x, then y = -16 1/16 16

Mathematics
2 answers:
emmasim [6.3K]3 years ago
7 0
Y = 4x
(-2,y).....x = -2

y = 4(-2)
y = -8
Korolek [52]3 years ago
6 0

Answer:

Step-by-step explanation:

(-2, y) lies on the graph of y = 4^x

It means for x=-2 we need to find the y =?

means we plug x=-2 in the given equation y = 4 ^x

so we get

y = 4^ (-2)

y = \frac{1}{4^2}

y = \frac{1}{16}

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What is how do I find m and b?
IrinaK [193]

Answer:

<h2>m = 21, b = 5 → y = 21x + 5</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept → (0, b)</em>

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

=====================================

From the table we have y-intercept (0, 5) → <em>b = 5 </em>and other point (1, 26).

Calculate the slope:

m=\dfrac{26-5}{1-0}=\dfrac{21}{1}=21

8 0
3 years ago
A cab company charges $10.00 per ride plus an additional .75 per mile write the problem in slope intercept form
Natalija [7]
Well the dependent variable is .75, and the independent variable is 10.

So,
.75x + 10 would be the equation, the number of miles representing x.


8 0
3 years ago
I need help with 11-14 please!
kumpel [21]
The answer to this question is 11-14 is -3
8 0
3 years ago
Consider this expression.
USPshnik [31]

Answer:

-16

Step-by-step explanation:

m^2 + n^2

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5 0
2 years ago
2. Draw the image of ∆RST under the dilation with scale factor ⅓ and center of dilation at the origin. Label the image ∆R’S’T’.
Alchen [17]
Since center of dilation is the origin, this is easy. Just divide all of the x and y coordinate values by 3. Place the new point on the graph, and draw the triangle.

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S' = S(-3,6)/3 = (-3/3,6/3)=(-1,2). So S'(-1,2)
T' = T(-6,-6)/3 = (-6/3,-6/3)=(-2,-2). So T'(-2,-2)

So you now know the location of the 3 new points. R' at (1,2), S' at (-1,2) and T' at (-2,-2). Simply draw those 3 points on your graph and connect the lines to make a new triangle.

6 0
3 years ago
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