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Dvinal [7]
2 years ago
11

If (-2, y) lies on the graph of y = 4x, then y = -16 1/16 16

Mathematics
2 answers:
emmasim [6.3K]2 years ago
7 0
Y = 4x
(-2,y).....x = -2

y = 4(-2)
y = -8
Korolek [52]2 years ago
6 0

Answer:

Step-by-step explanation:

(-2, y) lies on the graph of y = 4^x

It means for x=-2 we need to find the y =?

means we plug x=-2 in the given equation y = 4 ^x

so we get

y = 4^ (-2)

y = \frac{1}{4^2}

y = \frac{1}{16}

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The equation would be:
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Write the slope-intercept form of the equation of each line given the slope and y-intercept.
saul85 [17]

Answer:

4b. −6x + y = −4

4a. 7x + 4y = −12

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2a. y - 3 = ⅘(x - 5)

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Step-by-step explanation:

4.

Plug the coordinates into the Slope-Intercept Formula first, then convert to Standard Form [Ax + By = C]:

b.

2 = 6[1] + b

6

−4 = b

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-6x - 6x

_________

−6x + y = −4 >> Standard Equation

a.

4 = −7⁄4[-4] + b

7

−3 = b

y = −7⁄4x - 3

+7⁄4x +7⁄4x

____________

7⁄4x + y = −3 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]

4[7⁄4x + y = −3]

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__________________________________________________________

3.

Plug both coordinates into the Slope-Intercept Formula:

b.

5 = ½[4] + b

2

3 = b

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a.

−1 = −6[1] + b

−6

5 = b

y = −6x + 5

* Parallel lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>].

__________________________________________________________

2.

b. y + 2 = −⅔(x + 3)

a. y - 3 = ⅘(x - 5)

According to the <em>Point-Slope Formula</em>, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

__________________________________________________________

1.

b. y = -x + 5

a. y = 5x - 3

Just write out the Slope-Intercept Formula as it is given to you.

I am joyous to assist you anytime.

3 0
3 years ago
What is the area of the object above​
vivado [14]

Answer:

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Step-by-step explanation:

if you find the area of the entire shape (12x6) you can then subtract out the cut-out portion (5x2)

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5 0
2 years ago
Please help with this problem.
larisa86 [58]

Answer:

60°, 120°

Step-by-step explanation:

\frac{ {tan}^{2}x }{2}  - 2 {cos}^{2}x = 1 \\   \\  \frac{ {tan}^{2}x  - 4{cos}^{2}x }{2} = 1 \\  \\ {tan}^{2}x  - 4{cos}^{2}x = 2 \\  \\  \frac{{sin}^{2}x}{{cos}^{2}x} - 4{cos}^{2}x = 2 \\  \\ \frac{{sin}^{2}x - 4{cos}^{4}x}{{cos}^{2}x}  = 2 \\  \\ {sin}^{2}x - 4{cos}^{4}x = 2{cos}^{2}x \\  \\ 4{cos}^{4}x  + 2{cos}^{2}x - {sin}^{2}x = 0  \\  \\ 4{cos}^{4}x  + 2{cos}^{2}x  +  {cos}^{2}x  - 1= 0  \\  \\ 4{cos}^{4}x  + 3{cos}^{2}x   - 1= 0  \\  \\ 4{cos}^{4}x  + 4{cos}^{2}x -   {cos}^{2}x - 1= 0  \\  \\4{cos}^{2}x({cos}^{2}x + 1) - 1({cos}^{2}x + 1) = 0 \\  \\ ({cos}^{2}x + 1)(4{cos}^{2}x - 1) = 0 \\  \\ ({cos}^{2}x + 1) = 0 \: or \: (4{cos}^{2}x - 1) = 0 \\  \\ {cos}^{2}x =  - 1 \: or \: 4{cos}^{2}x = 1 \\  \\ {cos}x = \sqrt{ - 1}  \: which \: is \: not \: possible \\  \therefore \: {cos}^{2}x =  \frac{1}{4}  \\  \\ \therefore \: {cos}x =   \pm\frac{1}{2} \\  \\ \therefore \: {cos}x =   \frac{1}{2}  \: or \: {cos}x =    - \frac{1}{2}  \\  \\ \therefore \: {cos}x =   {cos}60 \degree \: or \: {cos}x =     {cos}120 \degree \\  \\ \therefore \:x = 60 \degree \:  \: or  \: \: x  = 120 \degree

6 0
3 years ago
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