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Sladkaya [172]
2 years ago
12

Which ordered pair is a solution to the inequality in the graph?

Mathematics
1 answer:
lukranit [14]2 years ago
5 0

Answer:

The answer is (1,5)

Step-by-step explanation:

Using Trial and Error. Substitute the values of x and y.

(-1, 0) = (x, y)

y ≤ 3x + 2

5 ≤ 3(1) + 2

5 ≤ 5

Five is less than or equal to five.

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Step-by-step explanation:

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12 times a number decreased by 5 is no more than 55
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Answer:

  12n -5 ≤ 55

Step-by-step explanation:

12 times a number (represented by n) is 12n.

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Then the expression written using math symbols is ...

  12n -5 ≤ 55

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Whats 20 inches and 7 feet as a fraction in simpalist form
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4 4/7 feet is it's simplest form because 20 I'm chea equal 1.67 feet and 7 feet equals 84 inches so do 20 × 4 = 80 then you would have 4 left over and turn that into 4/7
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ThE RADIUS of CIRCLE
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6 0
2 years ago
Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
3 years ago
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