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hoa [83]
3 years ago
12

Find the slope-intercept equation of the line

Mathematics
1 answer:
Natali [406]3 years ago
8 0

Answer:

y=8.

Step-by-step explanation:

all the details are in the attachment.

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-10 F is colder than -4 degrees?
Aleks04 [339]

Answer: yes, it is a smaller temperature, which means that is "colder"

Step-by-step explanation:

I guess that the question is:

Is -10°F colder than - 4°C?

Ok, when we have a temperature T in Celcius, the equation to transform this quantity to the Fahrenheit scale is:

T' = (T*9/5) + 32°

Replacing T by the temperature in celcius, we get:

T' = (-4°*9/5) + 32° = 24.8°F

This means that -4°C is equivalent to 24.8°F

And -10°F is a smaller value than 24.8°F (which mean that is colder)

This implies that -10°F is colder than -4°C

Then the statement is true.

4 0
3 years ago
How many servings in 3/4 of a cookie when each serving is 1/2 cookie
pishuonlain [190]
1 1/2 servings are in 3/4 bc 2/4= 1/2 and theres 1/2 a cookie left and if u take half of that it gets to 3/4
3 0
3 years ago
We are the smallest and largest whole numbers that round to 900000 when rounded to. the near.est ten th.ousand
Vinil7 [7]
It could be 85,000 and 94,000
5 0
3 years ago
Special right triangles.
Oliga [24]

QUESTION 9

The given right angle triangle has its two legs equal to x\:cm and the hypotenuse is 2\:units.


Using the Pythagoras theorem, we have

x^2+x^2=2^2


This implies that;

2x^2=2^2


2x^2=4


x^2=2


x=\sqrt{2}


x=1.414


x\approx1.4\:units


QUESTION 10


The given right angle triangle has its two legs equal to x\:units and the hypotenuse is 7\:units.


Using the Pythagoras theorem, we have

x^2+x^2=7^2


This implies that;

2x^2=7^2


2x^2=49


x^2=24.5


x=\sqrt{24.5}



x=4.95\:units


QUESTION 11

Sam divided the square backyard into two sections along the 40ft diagonal.

Let one of the sides of the garden be x\:units, then the other side of the garden is also  x\:units since it was a square backyard.


The diagonal is the hypotenuse which is 40ft and the two legs are  x\:units each.


Applying the Pythagoras Theorem, we have;

x^2+x^2=40^2


2x^2=1600


x^2=800


\Rightarrow x=\sqrt{800}


\Rightarrow x=28.28


The length of one side of the garden is approximately 28cm.


QUESTION 12

The hypotenuse of Nicole's right triangular support is 92cm long.


It was given that the two lengths of the triangular support are of equal length.


Let the two lengths of the triangular support be l\:cm each.


We then apply the Pythagoras theorem to obtain;

l^2+l^2=92^2


\Rightarrow 2l^2=8464


\Rightarrow l^2=4232


\Rightarrow l=\sqrt{4232}


\Rightarrow l=65.05cm


Therefore Nicole needs l+l=65.05cm+65.05cm\approx130cm of wood to complete the support.

The correct answer is A.


QUESTION 13

A 45-45-90 triangle is an isosceles right triangle.


Let the length of the two legs be m\:inches each.

It was given that the hypotenuse of this triangle is 12\:inches.


Applying the Pythagoras Theorem, we have;

m^2+m^2=12^2


\Rightarrow 2m^2=144


\Rightarrow m^2=72


\Rightarrow m=\sqrt{72}


\Rightarrow m=8.49


The length of one leg of the hypotenuse is approximately 8.5 inches to 1 decimal place.


QUESTIONS 14.

It was given that the distance from home plate to first base is 90 feet.


Since the baseball field form a square, the length of the baselines are all 90ft.

We want to calculate the distance from home plate to 2nd base,which is the diagonal of the square baseball field.

Let this distance be d\:ft, then using the Pythagoras theorem;

d^2=90^2+90^2


d^2=8100+8100


d^2=16200


\:d=\sqrt{16200}


\:d=127.279


Therefore the distance from home plate to second base is 127 ft to the nearest foot.


QUESTION 15.

The distance from third base to  first base is also 127 ft to the nearest foot.


The reason is that the  diagonals of a square are equal in length.


3 0
3 years ago
What is the function of this graph?
Lesechka [4]

Answer:

x=y^2-2

Step-by-step explanation:

This graph, is a parabola that opens to the right.

To answer this question, we just use the vertex form of a sideways parabola- x=a(y-k)^2+h.

In this case, the vertex is (-2, 0), and our value of a is 1, since it opens to the right.

This gives us: x=1(y-0)^2+(-2)

Which simplifies to: x=y^2-2.

Also, the answer to the previous two questions are wrong.

The D value (Domain) is actually [2, ∞)

The R value (Range) is actually "All real numbers" (-∞, ∞)

Let me know if this helps!

3 0
2 years ago
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