So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
A = 2.25 (3.14)
A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>
Answer:416
Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:
The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km
and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km
So add the given results above with 500 km and this will be the additional distance that plane moves through the air.
The answer would be in the unit meters.
((10√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
Answer:
1.4 times k
Step-by-step explanation:
If k feet is the distance from home plate to third base, and the distance from first base to third base is 1.4 times the previous value, then
distance from first base to third base = 1.4 * k or 1.4 times k
If, for example, k=90 feet, then from first to third base there are
1.4*90=126 feet
5p - 3q = -39
- (-2p - 3q = 3)
==> 7p = -42 ==> p = -6
==> p = -6
-2(-6) - 3q = 3 ==> 12 - 3q = 3
==>p = -6
-3q = 3 - 12 ==> -3q = -9
==> p = -6
q = 3
