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2 years ago

Help anyone I don’t understand this ????

Mathematics

1 answer:

Alexeev081 [22]2 years ago

5 0

The answer would be 0
You combine the first 2 “K” and that would make it k squared meaning it equals to 1 so now it’s 3k minus 3k so 0

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Find the sum of the first 9 terms of the geometric series:<br> 3 + 21 + 147 + …

grin007 [14]

Answer:

20,176,803

Step-by-step explanation:

This geometric series has a first term of 3 and a common ratio of 21/3 = 7. The formula for the sum of n terms of a series with first term a1 and common ratio r is ...

Sn = a1·(r^n -1)/(r -1)

For a1=3, n=9, and r=7, the sum is ...

S9 = 3·(7^9 -1)/(7 -1) = 3·40353606/6 = 20,176,803

The sum of the first 9 terms is 20,176,803.

_____

The first 9 terms are ...

3 +21 +147 +1029 +7203 +

50,421 +352,947 +2,470,629 +17,294,403

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2 years ago

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melamori03 [73]

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Crazy boy [7]

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3 years ago

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Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .

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Answer:

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2 years ago

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