Answer:
L (1, - 7 )
Step-by-step explanation:
give endpoints (x₁, y₁ ( and (x₂, y₂ ) then the midpoint is
( 
, 
)
here (x₁, y₁ ) = K (9, - 7 ) and (x₂, y₂ ) = L (x, y )
use the midpoint formula and equate to corresponding coordinates of M
= 5 ( multiply both sides by 2 to clear the fraction )
9 + x = 10 ( subtract 9 from both sides )
x = 1
and
= - 7 ( multiply both sides by 2 )
- 7 + y = - 14 ( add 7 to both sides )
y = - 7
Then L = (1, - 7 )
Gradient is the difference between the y-axis and the x-axis
Gradient = y2-y1/x2-x1
Choose any two point making a triangle
Line B (0,8) (4,0)
This makes a triangle please go look at the graph once again! The the triangle should not have half squares but full!
Line A (5,14)(2,2)
Now plug in the variable
The difference between the Y and X
Line B 0-8/4-0
Line B gradient =-2
Line A 2-14/2-5
Line A gradient = +4
Finalized answer
Line B gradient = -2
Line A gradient = +4
hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b = 1 (Center at the A(-2,1))
r = AP......P( -4 , 1)
r² = (AP)²
r² = (4+2)² +(1-1)² = 36
an equation of the circle that satisfies the stated conditions.
Center at </span></span> A(-2,1), passing through P(-4, 1) is : (x+2)² +(y-1)² = 36
B=90
I think this is the answer
