The ratio of right handed students to left handed students is 18:4. What are three ratios that are equivalent to the one give

An urn contain 2 white marbles, 3 green marbles, and 5 red marbles. A marble is drawn and then replaced. Then a second marble is

11111nata11111 [884]

Answer:

1/5

Step-by-step explanation:

To find this you would need to multiply the probability of pulling a white marble to the probability of pulling out a green marble.

1)First you would need the probability of pulling out a white marble. There are 10 marbles in total and out of those 2 are white. So the probability of pulling out a white marble would be 2/10. If you simplify that you would get 1/5 for the probability of pulling out a white marble.

2)Next, you would find the probability of pulling out a green marble. Using the same process that we used to find the probability of pulling out a white marble, we would find the answer to be 3/10. All that we did here was green marbles/total marbles. By filling that in we got 3/10 for the probability of pulling out a green marble.

3)Now all that is left is doing probability of pulling a white marble × probability of pulling out a green marble. This would be 1/5 × 3/10. After solving the answer would be 3/15 which we would simplify down to 1/5 as our final answer.

5 0

3 years ago

1. Evaluate 3y - 4 for y =5

irina1246 [14]

Answer:

1. Evaluate 3y - 4 for y =5

3*(5)-4=15-4=11

2. 65 + x = 99 x = ?

65+x=99

x=99-65

x=34

3. Find the product. 38.7 *21

38.7*21=812.7

4. Which value satisfies the equation? 9x + 3 = 30

The right value for x would be:

9x+3=30

9x=30-3

9x=27

x=27/9=3

Step-by-step explanation:

3 0

3 years ago

A bag contains 2 black balls, 4 yellow balls and 4 white balls. Event A is defined as drawing a white ball on the first draw and

arsen [322]

Answer: $P(B|A)=\dfrac{4}{9}$

Step-by-step explanation:

Given: A bag contains 2 black balls, 4 yellow balls and 4 white balls.

Event A is defined as drawing a white ball on the first draw.

Event B is defined as drawing a black ball on the second draw.

P(B|A) is expressed as the conditional probability of occurring B given that A.

i.e. it is the probability of happening B where A is already happended.

If a white ball is drawn at first, then the number of black ball(4) remains unchanged but the total number of balls (10) will become 9.

$Probability=\dfrac{Number\ of \ favorable \ outcomes}{Total\ outcomes}$

Then, $P(B|A)=\dfrac{4}{9}$

8 0

3 years ago

Solve for x: −3|2x + 6| = −12

spayn [35]

Start with

$-3|2x+6|=-12$

Divide both sides by -3

$|2x+6|=4$

If the absolute value of a number is 4, that number can either be 4 or -4: we have the two solutions

$2x+6=4 \iff 2x=-2 \iff x=-1$

$2x+6=-4 \iff 2x=-10 \iff x=-5$

8 0

3 years ago

Using Cramer’s Rule, what is the value of x in the system of linear equations below? x+3y=16 3x+y=8

alexdok [17]

Cramer's rule works as follows:
x+3y=16
3x+y=8
Then
x=Dx/D
y=Dy/D
where Dx,Dy,D are 2x2 matrices formed from of coefficients and right hand side.
D=
1 3
3 1
=1-9=-8
Dx=matrix D with first column replaced by the vector [16,8]=
16,3
8 1
=16-24
=-8

Dy=matrix D with second column replaced by the vector [16,8]=
1 16
3 8
=8-48
=-40

Therefore
x=-8/-8=1
y=--40/-8=5

Check:
x+3y=1+3(5)=16
3x+y=3(1)+5=8 ok.

4 0

2 years ago