It helps you because it makes it easier to divide you just have to keep using place value to find the quitent
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).
Answer:
7 days
Step-by-step explanation:
2000-600 is 1400.
1400/200 is 7
2000=200x+600
x=7
6x+12y-6z+7x7y-28z= 13x+19y-34z
Answer:
Step-by-step explanation:
You are trying to find the values of two quantities, so you will need to set up a system of two equations in two variables. We'll call M the price of a movie and V the price of a video game.
The first month: 3 movies, 8 video games, $55. Let's translate this into algebra:
3M + 8V = 55
The second month: 5 movies, 2 video games, $18. Translated:
5M + 2V = 18
Solve that system of equations
