What element is found in proteins,but not found in carbonhydrates

How scientists use repeated trials and replication in conducting experiments

puteri [66]

Scientists repeat the experiment to further prove it being correct, and they can replicate is with data, models, and other forms of proof of a correct hypothesis

6 0

3 years ago

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Why is suspect 1 considered more likely to have committed the crime than suspect 2?

ivanzaharov [21]

Answer: Because 1 is a smaller number

Explanation:

6 0

2 years ago

PLEASE SHORTEN SAMPLE ANSWER, PLS I RLLY NEED THIS

GaryK [48]

Answer:

here is the answer

Explanation:

Scarlet king snakes cannot camouflage and so instead they mimic a dangerous neighbor. Scarlet king snakes have evolved over the years to look like coral snakes so that they could scare away other predators that may be dangerous and would want to hurt them

this is the reason

----- now the simplified answer

the scarlet snake has a very random ( rare ) genetic variation , it mimcs or

( behaves a like or looks like coral snake ) , it turns out that this trait helps the snake high chance of survival, snake with this kind of trait are often likely to reproduce and pass their traits to their children

now most of the scarlet snakes have this trait

trait ; a distinguishing quality or characteristic, typically one belonging to a person.

thank you

4 0

4 years ago

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1.) You are studying P120, a protein of 120 KDa that is continuously synthesized in eukaryotic cells. Its cellular concentration

irina1246 [14]

Answer:

1. P120 is degraded in the 26S proteasome

2. The 26S proteasome has a major role in protein degradation and is critical for protein homeostasis

3. Cell cycle and DNA replication are cellular processes regulated by the Ras and NFkB pathways

Explanation:

The proliferation-associated nucleolar protein (p120) is a protein known to be expressed during the interphase of the cell cycle, specifically in G1 and early S phase, where any problem with DNA replication trigger a checkpoint, i.e., a molecular cascade of signaling events that suspend DNA replication until the problem is resolved. In mammalian cells, the 26S proteasome is responsible for catalyzing protein degradation of about 80% (or even more) of their proteins. The 26S proteasome acts to degrade rapidly misfolded and regulatory proteins involved in the cell cycle, thereby having a major role in protein homeostasis and in the control of cellular processes. It is for that reason that inhibitors that block 26S proteasome function have shown to be useful as therapeutic agents in diseases associated with the failure of protein degradation mechanisms (e.g., multiple myeloma). The NF-κB are highly conserved transcription factors capable of regulating different cellular processes including, among others, cellular growth, inflammatory responses and apoptosis. Moreover, the MAPK/ERK pathway is able to transduce different signals received on the cell surface to the nucleus. The MAPK/ERK pathway is activated when a singling molecule binds to a cell receptor which triggers a signaling cascade that ends when a transcription factor induces the expression of target genes, ultimately producing a response in the cell (for example, the progression through the cell cycle).

7 0

3 years ago

How many atp equivalents are consumed in the conversion of each of the following to a glucosyl residue in glycogen?

Nina [5.8K]

<h3><u>Answer;</u></h3>

Dihydroxyacetone phosphate - 1

Fructose-1,6-bisphosphate - 1

Pyruvate - 13

G-6-P - 1

<h3><u>Explanation;</u></h3>

1) Dihydroxyacetone phosphate = 1

G1P + GTP --> UDPG + PPi two P is equivalent to 2 ATP --->2 ADP + Pi) Therefore, two ATP equivalents - but UDP is the product and only one P needed

2 DHAP --> F1,6-BP -->F6P --> G6P -->G1P -->UDPG --> glucosyl residue

2) Fructose 1,6-bisphosphate = 1

3) Pyruvate = 13

2 pyr + 2 ATP --> 2 OAA

2 OAA + 2 GTP --> 2 PEP

2 PEP --> 2 2PG --> 2 3PG

2 3PG + 2 ATP --> 2 1,3 BPG

2 1,3 BPG + 2 NADH --> 2 G3P

2 NADH = 6 ATP

2 G3P --> DHP + G3P --> FDP -- > F6P + P

F6P --> G6P --> G1P

G1P + UTP --> UDPG + PP

4) Glucose-6-phosphate = 1

G6P -->G1P G1P + UTP --> UDP-GLC + 2 Pi

UDP-Glc + glycogen --> glycogen+ 1 Glc

4 0

3 years ago