28/11.2 = 2.5
since they are similar and openly stated as parrallelograms, you know that they have a scale of the longest edge of EFGH to the longest edge of JKLM
Y=-3x-11. you add the one to the other side making the equation y=-3(x+4)+1
then you distribute making it y=-3x-12+1
Answer:
B
Step-by-step explanation:
Answer:
triangles AQB and AVB are congruent.
ΔLKJ ≅ ΔLMJ
Step-by-step explanation:
We have to prove that triangles LKJ and LMJ are congruent so let's
Consider triangles LKJ and LMJ;
∠KLJ=∠MLJ {Given that LJ bisects ∠KLM}
∠KJL=∠MJL {Given that LJ bisects ∠MJK}
LJ=LJ {common side}
So using ASA, triangles AQB and AVB are congruent.
Hence it is proved that
ΔLKJ ≅ ΔLMJ
