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LenKa [72]
3 years ago
15

3x - 5 = 7x + 11 x =

Mathematics
2 answers:
Alexus [3.1K]3 years ago
7 0

Answer:

x= -4

Step-by-step explanation:

3x-5=7x+11

3x-5+5=7x+11+5

3x=7x+11+5

3x=7x+16

3x-7x=7x+16-7x

-4=7x+16-7x

-4x=16

divided each side by -4

x= 16 over -4

divide them and you get -4.

DanielleElmas [232]3 years ago
5 0

Answer:

3x - 5 = 7x + 11 \\ 7x - 3x =  - 11 - 5 \\ 4x =  - 16 \\x =  -  \frac{16}{4}   \\    \color{yellow} \boxed{x =-4}

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A measure of ________ for a numerical data set describes how its values vary with a single number
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NO LINKS!!
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Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

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which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

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2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

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25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

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