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tamaranim1 [39]
3 years ago
13

The sum of the square of a number and 34

Mathematics
2 answers:
Ne4ueva [31]3 years ago
5 0
Written as an expression, the statement 'the sum of the square of a number and 34' would look like this:

n^{2} +34

Hope that helped! =)
Zepler [3.9K]3 years ago
5 0

the complete question is

The sum of the square of 2 number is 34. The first number is one less than twice the 2nd number. Find the number


Let

2x-1-------> the first number

x------->the second number


we know that

(2x-1)^{2} +x^{2} =34\\ 4x^{2} -4x+1+x^{2} =34\\ 5x^{2} -4x-33=0\\ 5x^{2} -15x+11x-33=0\\ 5x*(x-3)+11*(x-3)=0\\ (5x+11)*(x-3)=0


therefore

x=3\\ 2x-1=5


the answer is

the numbers are

3,5

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Step-by-step explanation:

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The coordinates of A and B are (3k, 8) and (k, -3) respectively. Given that the gradient of the line segment AB is 3, find the v
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Step-by-step explanation:

gradient = slope or several other words.

it describes how strongly a line (or tangent to a bent curve) is going up or down or ... if it is changing at all.

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x changes by -2k (from 3k to k).

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so, the gradient or slope is

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1 year ago
Find the area of rectangle who’s length is 35 and diognal is 37
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Read 2 more answers
Find the geometric mean between each pair of numbers. sq root 49 and sq root841
vodomira [7]

<u>Answer:</u>

The geometric mean between each pair of numbers \bold{\sqrt{49} \text { and } \sqrt{841} \text { is } 14.24}

<u>Solution:</u>

The Geometric mean between two numbers a and b is given as  Geometric mean = \bold{\sqrt{ab}}   --- eqn 1

The Geometric Mean is a special type of average where we multiply the numbers together and then take a square root for the numbers.

From question, given that two numbers are \sqrt{49} and \sqrt{841}

Hence we can say “a” = \sqrt{49} =7  

Similarly “b” = \sqrt{841} = 29  

We have to find the geometric mean between “7” and “29”

By using equation 1,  

Geometric mean between 7 and 29 = \sqrt{7 \times 29} = \sqrt{203} = 14.24

Hence the geometric mean between \sqrt{49} \text { and } \sqrt{841} \text { is } 14.24

8 0
3 years ago
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