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Kitty [74]
3 years ago
5

I need help if you answer this I will give you 5 stars, a thank you and a brainiest

Mathematics
2 answers:
grigory [225]3 years ago
5 0

Answer:

200 / (3.14*(28/12)) = 27.3

Step-by-step explanation:

Lapatulllka [165]3 years ago
5 0

Answer:

88

Step-by-step explanation:

im not shrur

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I need help on algebra
boyakko [2]
Just remember the syllables PEMDAS which stand for Parentheses, Exponents, Multiplication, Division, Addition and Subtraction. If you can’t remember it, just write it on the side of your paper. But make sure to use it in that order.
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3 years ago
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Model 3+ (-4) on the number line
Anon25 [30]

Answer:

-1

Step-by-step explanation:

If u add 3 whole numbers to a negative number 4 then it'll equal -1. Think of it like 4-3 but add the negative sign at the begining

3 0
3 years ago
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Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
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What is the difference between the height and the slant height of a pyramid?
IRINA_888 [86]
The height is the measurement from the base to the top straight up.

The Slanted height is the height from base to top on one face of the pyramid.
8 0
3 years ago
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How to graph y=-4|x+2|-5
Elina [12.6K]
y= -4|x+2| -5 \\ \\x= -6 \Rightarrow y=-4|-6+2|- 5= -4|-4|- 5= -4*4 -5 =\\ \\=-16-5=-21\\  \\ \\x= -4\Rightarrow y=-4|-4+2|- 5= -4|-2|- 5= -4*2 -5 =\\ \\ =-8-5=-13\\ \\  \\x= -2 \Rightarrow y=-4|-2+2|- 5= -4|0|- 5= -4*0 -5 =-5\\ \\ \\x= 0 \Rightarrow y=-4|0+2|- 5= -4|2|- 5= -4*2 -5 =-8-5=-13\\ \\  \\x= 2 \Rightarrow y=-4|2+2|- 5= -4| 4|- 5= -4*4 -5 =-16-5=-21

4 0
3 years ago
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