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kondaur [170]
3 years ago
9

Round 12.462 to the tenths place

Mathematics
2 answers:
ollegr [7]3 years ago
6 0
The answer is 12.5, since 6 is over 5 4 goes to 5. 

Pepsi [2]3 years ago
5 0
The answer is 12.5 because it over five so it round up
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You have just used the network planning model and found the critical path length is 30 days and the variance of the critical pat
joja [24]

Answer:

0.726 is the probability that the project will be completed in 33 days or less.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30 days

Variance = 25 days

Standard Deviation,

\sigma = \sqrt{\text{Variance}} = \sqrt{25} = 5

We assume that the distribution of path length is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(completed in 33 days or less)

P( x \leq 33) = P( z \leq \displaystyle\frac{33 - 30}{5}) = P(z \leq 0.6)

Calculation the value from standard normal z table, we have,  

P(x \leq 33) = 0.726 = 72.6\%

0.726 is the probability that the project will be completed in 33 days or less.

8 0
3 years ago
What is the slope of a line that passes through (–4,–13) and (19,11)?
Anna11 [10]
For points (x1,y1) and (x2,y2)
slope=(y1-y2)/(x1-x2)

(-4,-13)
(19,11)
x1=-4
y1=-13
x2=19
y2=11

slope=(-13-11)/(-4-19)=-24/-23=24/23
B is answer
5 0
3 years ago
Read 2 more answers
What is the average rate of change between (3,2) and (1,9)
hjlf

Answer:

-0.25

Step-by-step explanation:

1-3= -2

9-2= 8

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7 0
3 years ago
Anyone know the awnser to this?
iragen [17]

Answer:

61

Step-by-step explanation:

straight line = 180 degree

to find the measure of angle QPR,

subtract 119 from 180

=>            180-119

=>            61

angle QPR = 61 degree

6 0
2 years ago
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TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN
stich3 [128]

Answer:

<u>A.</u> <u>It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

<u>45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Note: Same answer provided to question 14037480, answered by me.

7 0
3 years ago
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