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lesantik [10]
3 years ago
14

Form the quadratic equation whose one root is 2 + 2^(1/2)​

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0

9514 1404 393

Answer:

  x^2 -4x +2 = 0

Step-by-step explanation:

The other root is the conjugate of the given one, so is 2-√2. The quadratic equation in factored form is then ...

  (x -2-√2)(x -2+√2) = 0

Expanding this, we get ...

  (x -2)^2 -(√2)^2 = 0

  x^2 -4x +4 -2 = 0

  x^2 -4x +2 = 0 . . . . the equation you're looking for

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WHAT IS 24 DIVIDED BY 48 WITH WORK PLEASE
kotegsom [21]
So,

\frac{24}{48}

Write in prime factored form.
\frac{2*2*2*3}{2*2*2*2*3}

Cross-cancel
\frac{1}{2}
7 0
3 years ago
Read 2 more answers
A building's construction cost was $625,000. the building is 80 feet long, 45 feet wide and 12 feet high. what was the cost of t
Alborosie
Volume = Length x Width x Height 
Volume = 80 x 45 x 12
Volume = 43200 ft³

Cost per cubic foot = $625 000 ÷ 43200
Cost per cubic foot = $14.47

----------------------------------------------
Answer: $14.47 per cubic foot.
----------------------------------------------
8 0
3 years ago
Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more
Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1)         (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2)        (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3)        (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c)  + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

4 0
3 years ago
What is the square root of:<br><br>a) 58.82<br>b) 10
natka813 [3]
Square root of A= 7.66 ( Took the first 2 numbers after the decimal.)
Square root of B= 3.16 (Took the first 2 numbers after the decimal.)
HOPE THIS HELPS! ^_^
7 0
3 years ago
Consider this figure of a hexagon.
notsponge [240]
A)
It looks like the [irregular] hexagon has 3 rectangles and 2 triangles within it.
So let's exclude the triangular corners on bottom left and top right for now.
First we have a large rectangle covering most of the upper left of the polygon. 20 ft × 7 ft = 140 sq.ft.
Now we have a rectangle on the bottom right. The width is 11 ft, so take the 7 away from that, 4 ft. × 14 ft. on bottom. 4 ft × 14 ft = 56 sq.ft.
The last small rectangle fits on the right between the 2 other rectangles. It is 24-20 on top/bottom × 7-6 right/left. 4 ft × 1 ft = 4 sq.ft.
Now for the triangles: bottom left is 11-7 × 24-14 = 4 ft × 10 ft. 1/2bh = 1/2×10×4 = 20 sq.ft.
Top right is 24-20 × 11-5 = 4 ft × 6 ft. 1/2bh = 1/2×4×6 = 12 sq.ft.

B)
Add them all together for the total area (A):
A = 140 + 56 + 4 + 20 + 12 = 140+60+32
= 232 sq.ft.

Hope that explains it well enough! ;)
6 0
3 years ago
Read 2 more answers
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