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ivolga24 [154]
3 years ago
10

Shannon was born on 04/02/2004. How many eight-digit codes could she make using the digits in her birthday?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

24 eight-digit code.

Step-by-step explanation:

Frequency : 0 : 4

                    2 : 2

                    4 : 2

In total there are Eight (8) numbers and 3 frequent number ( which are 0, 2, 4 )

∴ 8 × 3 = 24.

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Reasoning uses facts, definitions, and accepted properties in a logical order to write a logical argument.
lidiya [134]

Answer:

B.

Step-by-step explanation:

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6 0
3 years ago
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If anyone knows how to obtain the answer, please notify me.
Tems11 [23]

Answer:

Area =  

b1 + b2

×h

2

=  

2 + 6

× 5

2

=  

20 centimeters2

Step-by-step explanation:

6 0
3 years ago
A manufacturer of shipping boxes has a box shaped like a cube. The side length is
Tatiana [17]
 The volume of a cube with side length equal to x, is V= x^{3}, 

thus, the volume of a cube shaped box, whose side length is (5a+4b) is :

V= (5a+4b)^{3},

The volume is already expressed in terms of a and b, but we can expand the expression (5a+4b)^{3}, as follows:

(5a+4b)^{3} =(5a+4b)(5a+4b)^{2}= (5a+4b)[ (5a)^{2}+2(5a)(4b)+ (4b)^{2}]

=(5a+4b)[ 25a^{2}+40ab+ 16b^{2}]

=(5a)[ 25a^{2}+40ab+ 16b^{2}]+(4b)[ 25a^{2}+40ab+ 16b^{2}]

=125a^{3}+200a^{2} b+ 80ab^{2}+100a^{2}b+160ab^{2} + 64b^{3}

125a^{3}+300a^{2} b+240ab^{2} + 64b^{3}


Answer:

V= (5a+4b)^{3},

or 

125a^{3}+300a^{2} b+240ab^{2} + 64b^{3}


7 0
3 years ago
tudents are given 3 minutes for each multiple-choice question and 5 minutes for each free-response question on a test. There are
AlladinOne [14]
In this question, they gave you the system of equations. You just need to use the two of them.

We want to find the m or the number of the multiple-choice questions. So we need to turn our last equation in the form of 'm's by translating the 'f's into 'm's.

m + f = 15
f = 15 - m

If we know the m form of f, we can convert the second equation and find the answer: 3m + 5f = 51

Plug in the m value of f: 3m + 5(15 - m) = 51

Distribute the 5: 3m + 75 - 5m = 51

Subtract -75 from both sides: 3m - 5m= 51 - 75

Combine like terms: - 2m = - 24

Divide both sides by -2: m = 12

So, we learned that the number of the multiple-choice questions is 12.
6 0
3 years ago
6 libras de café y 5 de azúcar costaron 227 pesos y 5 libras de café y 4 libras de azúcar (a los mismos precios) costaron 188 pe
nlexa [21]

Answer:

The price of one pound of coffee is 32 pesos

The price of one pound of sugar is 7 pesos

Step-by-step explanation:

The question in English is

6 pounds of coffee and 5 pounds of sugar cost 227 pesos and 5 pounds of coffee and 4 pounds of sugar (at the same prices) cost 188 pesos Find the price of one pound of coffee and one pound of sugar.

Let

x-----> the price of one pound of coffee

y-----> the price of one pound of sugar

we know that

6x+5y=227 -----> equation A

5x+4y=188 ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution is the point (32,7)

see the attached figure

therefore

The price of one pound of coffee is 32 pesos

The price of one pound of sugar is 7 pesos

6 0
4 years ago
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