Answer:
y = -3/1x + 2
Step-by-step explanation:
1. Find the slope
The points I will use are (-1,5) and (0,2), where x1 = -1, y1 = 5, x2 =0, and y2 =2.
y2-y1/x2-x1
2-5/0-(-1) = -3/1
2. Find the y-intercepy
y = mx + b
You can use any x or y point. I'll use (-1,5)
m= slope, which is -3/1
5= -3/1(-1) +b
5= 3 + b
Subtract 3 from 5 and 3 to get 2=b.
3. Rewrite in slope-intercept form
y = -3/1x + 2
<h3>
Answer:</h3>
y = 8/9x + 80/9
<h3>
Step-by-step explanation:</h3>
<u>We are given;</u>
- Equation of a line as 8x -9y -2 = 0
- Coordinates (-1,8)
We are required to determine the equation of a line parallel to the given line and passing through a point (-1,8)
<h3>Step 1: Determine the Gradient of the given line </h3>
- When an equation is written in the form y = mx + c, m is the gradient.
- Therefore; we could write the equation 8x -9y -2 = 0 in the form of y= mx + c
9y = 8x -2
y = 8/9x - 2/9
Therefore, the slope, m = 8/9
<h3>Step 2: Determine the equation of the line</h3>
- We need to know that parallel lines have the same gradient
- Therefore, the slope of the line in question is 8/9
- It passes through a point (-1, 8)
We can therefore, determine the equation;
Taking another point, (x,y)

9(y-8) = 8(x+1)
9y - 72 = 8x + 8
9y = 8x + 8 +72
9y = 8x + 80
y = 8/9x + 80/9
Therefore, the equation of the line is y = 8/9x + 80/9
Answer: x^5y^2
Step-by-step explanation: