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ch4aika [34]
3 years ago
8

Find the slope of the line on the graph.

Mathematics
1 answer:
Pani-rosa [81]3 years ago
4 0
The slope is -1/2 and the equation is y=-1/2x-4
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Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
What other information is needed to prove that Triangle CEB is congruent to Triangle AED by SAS congruence theorem?
Westkost [7]

Answer:

C

Step-by-step explanation:

Im pretty sure, but double check

3 0
3 years ago
Before 8 A.M., there were 64 trucks and 24 cars in a parking lot. Between 8 A.M. and 9 A.M., more cars entered the parking lot a
malfutka [58]

Answer:

232 cars

Step-by-step explanation:

Let's say the number of cars that entered is c.

At 9:00 am, there are a total of 24 + c cars and 64 trucks. We know that this value of 64 represents 1/5 of the total number of vehicles. The total number of vehicles is (24 + c) + 64 = 88 + c. So, we have:

64/(88 + c) = 1/5

Cross-multiply:

88 + c = 64 * 5 = 320

c = 320 - 88 = 232

Thus, the answer is 232 cars.

Note: as 232 doesn't show up in the answer choices, it's possible that the problem was copied correctly.

<em>~ an aesthetics lover</em>

6 0
3 years ago
Read 2 more answers
Can anyone simplify 24q2/8q-3
Morgarella [4.7K]
24q^2 / 8q^-3

lets break this down...
24/8 = 3

q^2 / q^-3....when dividing exponents with the same base, keep the base and subtract the exponents. q^2 / q^-3 = q^(2 -(-3) = q^(2 + 3) = q^5

put them together and u get : 3q^5
4 0
3 years ago
10 x 12 – 14 + 2 + 15 =​
kolbaska11 [484]

Answer:

Your answer of 10 x 12 - 14 +2+15 =123

8 0
3 years ago
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