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soldi70 [24.7K]
3 years ago
7

Answer the following questions.

Mathematics
1 answer:
Maslowich3 years ago
3 0

Answer:

The first is 12

The second is 25.35

Step-by-step explanation:

The second is confusing so sorry if I got that wrong

Please give brainelest

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What is the surface area, in square inches, of a disco ball with a circumference of 188.5 centimeters?
Rudik [331]
A = 11300 cm<span>2
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3 0
3 years ago
Select the correct answer.
liraira [26]

Answer:

c and d

Step-by-step explanation:

4 0
3 years ago
Find the equation of a line parallel to −5x+y=2 that contains the point (5,−2). Write the equation in slope-intercept form.
mario62 [17]

Answer:

L2: y-0 = 5/2(x-5)

y = 5/2x-25/2

Step-by-step explanation:

Parallel lines have same slopes.

Line 1,   L1:  5x-2y=20   is in standard form Ax+By=C therefore slope m1= -A/B = -5/-2 = 5/2 or you can solve it for y so you will have the equation in slope-intercept form.

5x-2y = 20

-2y = -5x+20

y = (-5/-2)x+20/(-2)

y = (5/2)x-10 hence m1=5/2 and y-intercept is -10

Line 2 , L2:   y-y1 = m (x-x1),  m=m2=m1=5/2

Point p(5,0) or p(x1,y1) therefore x1=5 , y1=0 and m=5/2

L2: y-0 = 5/2(x-5)

y = 5/2x-25/2

5 0
3 years ago
It costs $12 to attend a golf clinic with mr. Stephan. Buckets of golf balls cost $3 each. How much can you buy if you have $30
Talja [164]
You can buy 6 buckets
Explanation:
12-30=18
18 divided by 3=6
4 0
3 years ago
During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this
alex41 [277]

Answer:

Step-by-step explanation:

Given that during  the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt

Resolve into partial fractions

\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}

Integrate to get

ln P -0.00474/0.0001489  (ln (0.0001489P-0.03135) = t+C

ln P -31.833  (ln (0.0001489P-0.03135) =t+C

\frac{P}{( ( (0.0001489P-0.03135)^{31.833}  } =Ae^t

Limiting population would be infinity.

6 0
4 years ago
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