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icang [17]
3 years ago
12

A 20-ounce candle is expected to burn for 60 hours. A 12-ounce candle is expected to burn for 36 hours. Assuming the variables a

re directly related, how many hours would a 9-ounce candle be expected to burn?
18
27
33
45
Mathematics
2 answers:
lawyer [7]3 years ago
8 0
Divide size of candle by number of hours
 to find the rate it burns:

20 ounce / 60  hours = 1/3 ounce per hour 

divide 9 ounces by 1/3 ounce per hour to find total time:

9 / 1/3 = 27 hours
ratelena [41]3 years ago
3 0

Answer:

B. 27.

Step-by-step explanation:

We have been given that a 20-ounce candle is expected to burn for 60 hours. A 12-ounce candle is expected to burn for 36 hours.

We know that a direct proportional equation is in form y=kx, where k represents constant of proportionality.

Let is find value of k by substituting x=20 and y=60 in above equation as:

60=k*20

\frac{60}{20}=\frac{k*20}{20}

3=k

The equation y=3x represents our given direct proportional relation.

Now, we will substitute x=9 to solve for y as:

y=3*9

y=27

Therefore, a 9-ounce candle would be expected to burn for 27 hours and option B is the correct choice.

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Solve the following equation with variables on both sides and one side only:
elena-s [515]

Answer:

How to solve your question

Your question is

8+3−3=−52

8x+3-3x=-528x+3−3x=−52

Solve

1

Combine like terms

8+3−3=−52

}=-528x+3−3x=−52

5+3=−52

−52

2

Subtract 

3

33

 from both sides of the equation

5+3=−52

5x+3=-525x+3=−52

5+3−3=−52−3

5x+3

5x+3−3=−52−3

3

Simplify

Subtract the numbers

Subtract the numbers

5=−55

7 0
3 years ago
Read 2 more answers
What is 68 divided by 5 ??
FinnZ [79.3K]
68 Divided by 5 is 13.6
5 0
3 years ago
Read 2 more answers
G verify that the divergence theorem is true for the vector field f on the region
Alenkasestr [34]
\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1

Converting to spherical coordinates, we have

\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi

On the other hand, we can parameterize the boundary of E by

\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle

with 0\le u\le2\pi and 0\le v\le\pi. Now, consider the surface element

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv
=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi

as required.
3 0
4 years ago
the ratio of strawberry to banana batter is 2:3. We need 30 cups of batter total. What percent of the cake is banana.
frutty [35]
70% is the correct answer to this i think
7 0
4 years ago
an engineer estimates that 30% of gasoline is used efficiently by a car. how many gallons,out of 20 gallons, are used efficientl
juin [17]

We need to find 30% of 20 gallons.

1) We can write a proportion

20 gallons ---- 100%

x gallons --------30%

x = 20*30/100 = 6 gallons

2) Or we can write 30% as decimal.

30% = 30/100 = 0.3

0.3 of 20 = 0.3*20 =6 gallons

Answer 6 gallons are used efficiently.

3 0
3 years ago
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