The answer would be 10.976.
Answer:
The Parenthesis tells you what operation to do first.
Step-by-step explanation:
Why? Because you have to get rid of the Parenthesis before getting rid of anything else in the problem.
The product of √3 and 5√3 in its simplest form is 15.
<h3>What is a rational number?</h3>
A rational number is defined as a numerical representation of a part of a whole that represents a fraction number.
It can be a/b of two integers, a numerator a, and a non-zero denominator b.
To determine the product of √3 and 5√3
So, (√3 )(5√3)
⇒ 5 (√3 )(√3 )
⇒ 5(3)
⇒ 15
The result is rational because 15, can be expressed as a ratio of two integers can be 15/1 of two integers, a numerator 15, and denominator 1 ( which is a non-zero).
Thus, the result is rational.
Learn more about rational numbers here:
brainly.com/question/10354322
#SPJ1
Answer: Choice B. k(h(g(f(x))))
For choice B, the functions are k, h, g, f going from left to right.
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Explanation:
We have 4x involved, so we'll need f(x)
This 4x term is inside a cubic, so we'll need g(x) as well.
So far we have
g(x) = x^3
g( f(x) ) = ( f(x) )^3
g( f(x) ) = ( 4x )^3
Then note how we are dividing that result by 2. That's the same as applying the h(x) function
![h(x) = \frac{x}{2}\\\\h(g(f(x))) = \frac{g(f(x))}{2}\\\\h(g(f(x))) = \frac{(4x)^3}{2}\\\\](https://tex.z-dn.net/?f=h%28x%29%20%3D%20%5Cfrac%7Bx%7D%7B2%7D%5C%5C%5C%5Ch%28g%28f%28x%29%29%29%20%3D%20%5Cfrac%7Bg%28f%28x%29%29%7D%7B2%7D%5C%5C%5C%5Ch%28g%28f%28x%29%29%29%20%3D%20%5Cfrac%7B%284x%29%5E3%7D%7B2%7D%5C%5C%5C%5C)
And finally, we subtract 1 from this, but that's the same as using k(x)
![k(x) = x-1\\\\k(h(g(f(x)))) = h(g(f(x)))-1\\\\k(h(g(f(x)))) = \frac{(4x)^3}{2}-1\\\\](https://tex.z-dn.net/?f=k%28x%29%20%3D%20x-1%5C%5C%5C%5Ck%28h%28g%28f%28x%29%29%29%29%20%3D%20h%28g%28f%28x%29%29%29-1%5C%5C%5C%5Ck%28h%28g%28f%28x%29%29%29%29%20%3D%20%5Cfrac%7B%284x%29%5E3%7D%7B2%7D-1%5C%5C%5C%5C)
This leads to the answer choice B.
To be honest, this notation is a mess considering how many function compositions are going on. It's very easy to get lost. I recommend carefully stepping through the problem and building it up in the way I've done above, or in a similar fashion. The idea is to start from the inside and work your way out. Keep in mind that PEMDAS plays a role.