Complete question:
y = 2x² + 2x - 3
x = -2 -1 0 1 2
Answer:
<u>Complete table of values</u>
x: -2 -1 0 1 2
y: 1 -3 -3 1 9
Step-by-step explanation:
Given;
y = 2x² + 2x - 3
To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.
when, x = -2
y = 2(-2)² + 2(-2) - 3
y = 8 - 4 - 3
y = 1
when x = -1
y = 2(-1)² + 2(-1) - 3
y = 2 - 2 - 3
y = -3
when x = 0
y = 2(0)² + 2(0) - 3
y = 0 - 0 - 3
y = -3
when x = 1
y = 2(1)² + 2(1) - 3
y = 2 + 2 - 3
y = 1
when x = 2
y = 2(2)² + 2(2) - 3
y = 8 + 4 - 3
y = 9
<u>Complete table</u>
x: -2 -1 0 1 2
y: 1 -3 -3 1 9
Answer:
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Step-by-step explanation:
THE BEST RAPPPERRR!!!!!!!!!
Answer:
D. 18.9 ÷ 9
Step-by-step explanation:
we need to divide
1.89 ÷ 0.9 but write it in different form
so ,we need to eliminate decimal from 0.9
as 0.9*10 = 9
thus,we multiply both 1.89 and 0.9 with 10, then we will have
(1.89*10) ÷ (0.9*10)
=> 18.9 ÷ 9
Thus, based on above calculation new look would be D. 18.9 ÷ 9
Answer:
3x2+15x+30 with a remainder of 68
Answer: Dimensions of A are of length [L]
Dimensions of B are of 
Dimensions of C are of 
Step-by-step explanation:
The given equation is
Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid
Thus
Dimensions of A = [L]
Dimensions of Bt = [L]
![Bt=[L]\\\\](https://tex.z-dn.net/?f=Bt%3D%5BL%5D%5C%5C%5C%5C)
![[B][T]=[L]](https://tex.z-dn.net/?f=%5BB%5D%5BT%5D%3D%5BL%5D)
![\\\\\therefore [B]=LT^{-1}](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Ctherefore%20%5BB%5D%3DLT%5E%7B-1%7D)
Similarly
Dimensions of ![Ct^{}2 = [L]](https://tex.z-dn.net/?f=Ct%5E%7B%7D2%20%3D%20%5BL%5D)
![Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}](https://tex.z-dn.net/?f=Ct%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5BC%5D%5BT%5D%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5Ctherefore%20%5BC%5D%3DLT%5E%7B-2%7D)
