the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Subtract 2x from each side
2x+3=4x+1
-2x -2x
3=2x+1
subtract 1 from each side
3=2x+1
-1 -1
2=2x
divide each side by 2
2=2x
1=x
Answer:
Idk
Step-by-step explanation:
Answer:
,
,
and 
Step-by-step explanation:
Here, x represents the number of hours Zoe spent running on her wheel and y represents the number of hours spent scratching her cage.
Julie was awoke for at least an hour running on her exercise wheel and scratching the of her cage.
⇒ 
She ran on her wheel at least twice as long as she scratched at the corners of her cage.
⇒ 
Also, She spent more than 1/4 hour running on her wheel.
⇒ 
And, we know that number of hours can not be negative.
⇒
Therefore, the complete system of inequality which shows the given situation is,
,
and
, 
Note: the feasible region ( covered by the given system) is shown in the below graph.
Answer:
C
Step-by-step explanation:
Firstly, we know that the function must be negative due to its shape. This means that the answer cannot be B
Next we can use the equation
that is used in order to find the vertex of the parabola.
A)

As the vertex is at x=3 on the graph, this one could be a contender.
C)

This also could be the equation
D)

This rules option D out.
For this last step, we can look at where the zeroes would be for each equation. (These values are irrational, so we cannot look at specific number)
A)

As this equation has a negative value for c, this means that one zero must be positive and the other must be negative.
This means that option A can be ruled out
C)

As this equation has a positive value for c, this means that both of the zeroes must be positive. This means that it is the only one that fits all of the criteria.