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KIM [24]
3 years ago
10

Find the missing angles

Mathematics
1 answer:
o-na [289]3 years ago
8 0

Answer:

<b= 36 degrees, <c= 144 degrees

Step-by-step explanation:

144 and b are supplementary meaning they add up to 180.

144 and c are vertical angles meaning they are congruent.

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I need help on these please ​
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Answer:

its the third answer, fifth, and first. Im not sure tho.

Step-by-step explanation:

if it isnt right im so sorry T^T

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The radius of a basketball is 4.7 inches.what the volume of the basketball? Round to the nearest 10
asambeis [7]
The formula for the volume of a sphere is V= \frac{4}{3}  \pi r^3. Plugging in 4.7 for your radius, we get V= \frac{4}{3} \pi 4.7^2= \frac{4}{3} \pi 22.09= \frac{88.36}{3} \pi, which is roughly 29.453π≈92.530.
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23. Mr. Gomez bought fruit to make fruit salad. He bought 2 poundsFruit of apples and spent $4.50 on apples and oranges. Write a
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Equation: $1.20 x 4 = $4.80. This means that Mr. Gomez could've bought 2 of each fruit (because they cost the same)
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A study of the pricing accuracy of checkout scanners at a store found that one of every 20 items is priced incorrectly. On any g
GalinKa [24]

Answer:

a) There are going to be at least 15 items both priced correctly, and incorrectly, which means that we can use the normal approximation to the binomial to solve the exercise in this supposed problem.

b) 20.36% probability that exactly one of the five items is priced incorrectly by the scanner

c) 22.62% probability that at least one of the five items is priced incorrectly by the scanner

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is priced correctly, or it is not. The probability of an item being priced incorrectly is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Five items selected.

This means that n = 5

One of 20 is priced incorrectly.

This means that p = \frac{1}{20} = 0.05

a) Assuming that this store sells thousands of items every day, which probability distribution would you use and why?

There are going to be at least 15 items both priced correctly, and incorrectly, which means that we can use the normal approximation to the binomial to solve the exercise in this supposed problem.

b) What is the probability that exactly one of the five items is priced incorrectly by the scanner?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.05)^{1}.(0.95)^{4} = 0.2036

20.36% probability that exactly one of the five items is priced incorrectly by the scanner

c) What is the probability that at least one of the five items is priced incorrectly by the scanner?

Either no items are priced incorrectly, or at least one is. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 0

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.05)^{0}.(0.95)^{5} = 0.7738

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7738 = 0.2262

22.62% probability that at least one of the five items is priced incorrectly by the scanner

5 0
3 years ago
The cost to rent a moving van is $14 plus an additional $9 per hour. For $50, what is the
irina1246 [14]
4hours hope this help. 14+9=23+9=32+9=41+9=50
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