Given the following function:
![\text{ f(x) = }\sqrt[]{-x\text{ -2}}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x%5Ctext%7B%20-2%7D%7D%5Ctext%7B%20%2B%202%7D)
y = f(x)
Therefore, let's complete the data table by substituting each x-values to be able to get the respective y-values,
We get,
At x = -2,
![\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20y%20%3D%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{f(-2) = }\sqrt[]{-(-2)-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7Bf%28-2%29%20%3D%20%7D%5Csqrt%5B%5D%7B-%28-2%29-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{ = }\sqrt[]{2\text{ - 2}}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B2%5Ctext%7B%20-%202%7D%7D%5Ctext%7B%20%2B%202%7D)
![\text{ = }\sqrt[]{0}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B0%7D%5Ctext%7B%20%2B%202%7D)
Therefore, y = 2 at x = -2.
At x = -3,
![\text{f(-3) = }\sqrt[]{-(-3)-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7Bf%28-3%29%20%3D%20%7D%5Csqrt%5B%5D%7B-%28-3%29-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{= }\sqrt[]{3-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%3D%20%7D%5Csqrt%5B%5D%7B3-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{= }\sqrt[]{1}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%3D%20%7D%5Csqrt%5B%5D%7B1%7D%5Ctext%7B%20%2B%202%7D)
Therefore, y = 3 at x = -3.
At x = -6,
Answer:
The answer should be c
Step-by-step explanation:
whenever you are trying to determine whether a graph determines a function or not, just draw a vertically straight line through the graph's line. If you draw that line and it goes through the graph's line more than once, then the graph does not represent a function.
Answer:
{-7, 2, 8}
Step-by-step explanation:
We see that the domain is limited to three x-values: -3, 0 and 2. To find the range (which is the set of all y-values) we just need to plug-in these x-values and find the corresponding y-values.
So our equation is:
y = 3x + 2
Then we substitute for the x-values:
y = 3(-3) + 2
y = -9 + 2
y = -7
y = 3(0) + 2
y = 0 + 2
y = 2
y = 3(2) + 2
y = 6 + 2
y = 8
So our range would be {-7, 2, 8}.
Answer:
35*14-16=x
Step-by-step explanation:
Answer:
Part A:
All of her steps are correct except for Step 4. When solving inequalities, when you multiply or divide by a negative number, you have to reverse the sign.
Part B:
Copy her Steps 1-3.
For your last step, (Step 4), you should instead write x>-8/7.
