Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
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Answer:
The answer should be C
Step-by-step explanation:
Answer:
D.) 1 + 1 + 5/8 + 2/8
Step-by-step explanation:
1 5/8 + 1 1/4
*set aside ones for a sec*
1/4 x 2/2 = 2/8
5/8 + 2/8
*get the ones back in*
1 + 1 + 5/8 + 2/8
Answer:
4
Step-by-step explanation:
Func 2 is -2
Func 3 is 1
Func 4 is 8
Func 1 is unknown
