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Romashka [77]
3 years ago
7

(-8r^2s^-8)(-3r^-7s^8)

Mathematics
2 answers:
Monica [59]3 years ago
7 0

24r^−5s0  Eliminate redundant parentheses,Multiply the numbers

sertanlavr [38]3 years ago
4 0

24r^−5s^0 would be your answer

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Answer:

Only natural numbers (i.e., non-negative integers) can be the exponents of variables in a polynomial.

Step-by-step explanation:

The exponent of variables in a polynomial should be natural numbers (0, 1, 2, 3, \dots.)

  • \sqrt{2\, x} is equal to \sqrt{2}\, x^{1/2}. In this expression, x is the variable. Its exponent is 1/2, which isn't a natural number.
  • On the other hand, \sqrt{2}\, x is equivalent to \sqrt{2}\, x^{1}. The exponent of variable x is 1, which is indeed a natural number.

\sqrt{2\, x} isn't a polynomial because the exponent of variable x isn't a natural number. On the other hand, \sqrt{2}\, x is indeed a polynomial over the set of real numbers.

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A function f(x) is graphed. What is the slope of the function? m= What is the y-intercept of the function? b= Which equation rep
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