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MA_775_DIABLO [31]

3 years ago

6

Which of the following is best described as a three-dimensional solid consisting of a base that can be any polygon a point not i

n the same plane as the polygon and all points between them? A. Triangular prism B. cube C. Rectangular prism D. Pyramid

1 answer:

Harman [31]3 years ago

3 0

Answer:

Option D

Pyramid

Step-by-step explanation:

The clause that gave away the answer is "<em>three-dimensional solid consisting of a base that can be any polygon"</em>

<em></em>

Scanning through the options, we can see that the only option that fits the description is the pyramid.

The pyramid is the only three-dimensional shape amongst the options that can take any polygon as a base.

<em>The other options get screened out here.</em>

A cube must have a square base.

A triangular prism must have a triangular base

A rectangular prism must have a rectangular base

Thus, option D: The Pyramid is the correct answer.

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Jane has three boxes she needs to ship. Box X weighs 33 kg more than Box Y and Box Z weighs 12 kg more than Box Y. She

andreyandreev [35.5K]

Answer:

$3w+45=557$

Step-by-step explanation:

Let the weight of box Y be w kg.

Box X weighs 33 kg more than Box Y, then the weight of box X is

$w+33$ kg.

Box Z weighs 12 kg more than Box Y, then the weight of box Z is

$w+12$ kg.

The total weight of all boxes is

$w+(w+33)+(w+12)=w+w+33+w+12=3w+45$ kg

Jane measured the total weight of all the boxes and it was found to be 557 kg, therefore,

$3w+45=557$

or

$3w=512$

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3 years ago

Diego played chess for 30 minutes. He stopped playing at 5:49 PM move the numbers to the Clock to show what time he started play

Sidana [21]

Answer:

He strated at 5:19 PM

Step-by-step explanation:

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3 years ago

Read 2 more answers

How do I solve: 6x^2 -x-12=0 ^2 means squared by the way!

Alchen [17]

$6x^2 -x-12=0\\
6x^2+8x-9x-12=0\\
2x(3x+4)-3(3x+4)=0\\
(2x-3)(3x+4)=0\\
x=\frac{3}{2} \vee x=-\frac{4}{3}
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3 years ago

What is the area of the front of the rectangular prism?

iVinArrow [24]

Answer:

Area = 28 cm² (check the attached diagram for better clarity)

Step-by-step explanation:

The question is incomplete but let's see a similar example

The front of a rectangular pyramid can refer to either one of two possibilities: it could be either the side that has the breadth and the height or the side that has the length and the height. In this case, we were given the formula for calculating the area of the front face of this rectangular prism as the product of breadth and height

Mathematically,

A = bh

From the attached diagram, we will see the properties of the rectangular prism as:

length = 5 cm, breadth = 4 cm, height = 7 cm

To calculate for the front face, we use A = bh,

⇒ A = 4 * 7 = 28 cm²

Example 2

If the breadth of the rectangular prism is 2 cm and the height is 3 cm, we have:

A = 2 * 3 = 6 cm²

7 0

3 years ago

The letters in the word STATISTICS are printed on identical index cards with one letter per card. The ten cards are

Alex17521 [72]

Answer:

a.

Outcome ---------- Probability

S -------------------------- 0.3

T -------------------------- 0.3

A -------------------------- 0.1

I --------------------------- 0.2

S -------------------------- 0.1

b.

$P(V) = 2/10$

$P(F) = 2/10$

c.

Events V and F are not mutually exclusive

Step-by-step explanation:

Given

$Text: STATISTICS$

Solving (a): Outcomes and Probabilities

The text is made of the following makeup.

$S = 3$

$T = 3$

$A = 1$

$I = 2$

$C = 1$

$Total = 10$

The probability of each outcome is calculated by dividing the occurrence of each alphabet by the total number of alphabets

So:

$S = 3/10 = 0.3$

$T = 3/10 = 0.3$

$A = 1/10 = 0.1$

$I = 2/10 = 0.2$

$C = 1/10 = 0.1$

In tabular form, we have:

Outcome ---------- Probability

S -------------------------- 0.3

T -------------------------- 0.3

A -------------------------- 0.1

I --------------------------- 0.2

S -------------------------- 0.1

Solving (b)

$V = Vowels$

$F = A - M$

Calculating P(V)

P(V) = Number of vowels divided by total

The vowels are A and I.

So, number of vowels is 2

$P(V) = 2/10$

Calculating P(F)

P(F) = Number of alphabets from A to M divided by total

Alphabets from A and M are A and I

So, number of alphabets in this category is 2

So:

$P(F) = 2/10$

Solving (c):

Events V and F are not mutually exclusive because both can occur at the same time.

i.e.

An event can be a vowel and still be between A and M

3 0

2 years ago